I need help solving this I’m not to good at math plz

Order each set of numbers from least to greatest.<br><br><br> PLZ HELP ASAP

Wittaler [7]

Answer:

$\frac{41}{3} < 14 < \sqrt{200}$

<u> $0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} }$ </u>

Step-by-step explanation:

$\sqrt{200} = 10 \sqrt{2} = 14.1 \\ 14 = 14 \\ \frac{41}{3} = 13.6$

So ;

$\frac{41}{3} < 14 < \sqrt{200} \\ 13.6 < 14 < 14.1$

$\frac{2}{3} = 0.66 \\ \sqrt{ \frac{9}{16} } = \frac{3}{4} = 0.75 \\ 0.6 = 0.6$

So ;

$0.6 < \frac{2}{3} < \sqrt{ \frac{9}{16} } \\ 0.6 < 0.66 < 0.75$

I hope I helped you^_^

6 0

2 years ago

What is 5/6 divided by 1 5/6

Lana71 [14]

Answer:

0.45454545454, also known as 0.45 repeated

Step-by-step explanation:

5 0

2 years ago

Read 2 more answers

A rug maker is using a patter that is a rectangle with a length of 96 inches and a width of 60 inches. the rug maker wants to in

dexar [7]

Recall that the formula for the perimeter of a rectangle is: 2Length+2Width
With this in mind, we have that the original design is 96×60, where 90 is length and 60 is width, so it would simply be:
2(96+l) + 2 (60+w) = New Perimeter
Or simplified, it'd be:
2l + 2w + 312 = New Perimeter

8 0

2 years ago

If outliers are discarded, then the retirement savings by residents of Econistan is normally distributed with a mean of $100,000

zavuch27 [327]

Answer:

$P(X>117000)=P(\frac{X-\mu}{\sigma}>\frac{117000-\mu}{\sigma})=P(Z>\frac{117000-100000}{20000})=P(z>0.85)$

And we can find this probability using the complement rule and the normal standard table or excel:

$P(z>0.85)=1-P(z$

The firgure attached illustrate the problem

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

Solution to the problem

Let X the random variable that represent the retirement savings of a population, and for this case we know the distribution for X is given by:

$X \sim N(100000,20000)$