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seropon [69]
2 years ago
15

What is the equation of the graph in slope-intercept form?

Mathematics
1 answer:
Slav-nsk [51]2 years ago
7 0
The answer is B y=4x-6
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You downloaded a video game to your computer. You have a 60-minute free trial of the game. It takes 5 minutes to set up the game
Luba_88 [7]

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I think the equation is 7l +5=60

Step-by-step explanation:


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X — бу + 2x = 5 2x – 3y+z = 4 3х +4y - z = -2
icang [17]
Solve the following system of equations for x: 4x + 6y = 68 2x + 6y = 76  A. x = - 14 B. None of these. C. x = - 4 D. x = 14 E. x = 4
Top answer · 3 votes
option C is correct More
7 0
3 years ago
The actual length of c in the triangle shown is 15 cm.
Strike441 [17]
The answer is B. Hope this helps!
4 0
2 years ago
Read 2 more answers
The length of a rectangle is 5 inches more than its width, x. The area of a rectangle can be represented by the equation x2 + 5x
nikdorinn [45]

Answer:

  width: 15 inches; length: 20 inches

Step-by-step explanation:

The equation tells you the product of width (x) and length (x+5) is 300, so you're looking for factors of 300 that differ by 5.

  300 = 1·300 = 2·150 = 3·100 = 4·75 = 5·60 = 6·50 = 10·30 = 12·25 = 15·20

The factors in the last pair on this list differ by 5, so we have ...

  • width = 15 inches
  • length = 20 inches
5 0
3 years ago
The alternating current (AC) breakdown voltage of an insulating liquid indicates its dielectric strength. The article "Testing P
zysi [14]

Answer:

Step-by-step explanation:

Hello!

Given the variable

X: breakdown voltage of an insulating liquid under certain conditions.

a)

Graphic in attachment.

Box: The median is closer to the third quartile than the first quartile showing skewness to the left.

The black dot in the middle of the box represents the sample mean (X[bar]) as you can see it is also moved to the right side of the distribution, affected by the presence of an outlier.

Whiskers:

The upper whisker is smaller than the lower one and there is a value that can be considered an outlier.

Altogether you can say that the distribution of the data set is skewed to the left.

b)

To estimate the population mean you need the population to be at least normal. The box plot shows that the distribution is not symmetrical but, considering that the sample size is n= 48 you can apply the Central Limit Theorem and approximate the sampling distribution to normal.

X[bar]≈N(μ;σ²)

As the distribution is approximate, using the sample standard deviation (since we don't know the population value) for the distribution standard deviation is also valid ⇒ Z= \frac{X[bar]-Mu}{\frac{S}{\sqrt{n} } }

X[bar] ± Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

∑X= 2626 ∑X²= 144950 n= 48

X[bar]= ∑X/n= 2626/48= 54.71

S²= 1/n[∑X²- (∑X)²/n]= 1/47[144950-(2626)²/48]= 27.36

S= 5.23

Z_{1-\alpha /2}= Z_{0.975}= 1.96

54.71 ± 1.96 * \frac{5.23}{\sqrt{48} }

[53.22; 56.18]kV

c)

95% CI

amplitude a=2 kV  i.e. semi amplitude d= 1 kV

The semi amplitude or margin of error for the CI can be calculated as:

d= Z_{1-\alpha /2} * \frac{S}{\sqrt{n} }

From this formula you can clear the sample size

\frac{d}{Z_{1-\alpha /2}} = \frac{S}{\sqrt{n} }

(\frac{d}{Z_{1-\alpha /2}} )*\sqrt{n} = S

\sqrt{n} = S* (\frac{Z_{1-\alpha /2}}{d} )

n = (S* (\frac{Z_{1-\alpha /2}}{d} ))^2

n= (5.23*(\frac{1.96}{1} ))^2= 105.08= 106

3 0
3 years ago
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