Answer:
yes
Step-by-step explanation:
Answer:
21°
Step-by-step explanation:
We can prove these two triangles congruent by the HL (Hypotenuse-Leg) theorem. Then, we know that m<YQR is congruent to m<PQY. We can then use their given values to form an equation.
5x+6=16x-27
Continue to solve . . .
33 = 11x
x=3
Therefore, we can plug this value of 3 into the expression for the value of m<YQR, and you will get
(16 x 3) - 27, which is equal to 21°.
Answer:
they are equal
Step-by-step explanation:
Consider the right triangle ABC with sides a, b, and c as shown in the figure.
Let m(\angle A)=\alpha, and m(\angle B)=\beta.
\alpha +\beta=90^{\circ}, so angles A and B are complementary.
According to the definition of sine, and cosine:
\displaystyle{ \sin \alpha= \frac{opposite\ side}{hypotenuse} =\frac{a}{c} , and
\displaystyle{ \cos \beta= \frac{adjacent\ side}{hypotenuse} =\frac{a}{c}
Answer:
no it is not
Step-by-step explanation:
i drew the line bc in order for it to be a function there would have to be only one point in each line
hopefully this helps :)
have a nice day !!
44 = 11
---- ----
p 5
Cross multiply
44*5 = 11p
You end up with ;
220 = 11p
Divide 220 by 11 to get p by itself
20 = p <-- that's your answer
hope i helped :)
