Magnitude of initial velocity
<em>To calculate the </em><em>magnitude</em><em> of the </em><em>velocity</em><em> at any point in time, multiply the constant acceleration rate times the time difference and then add it to the </em><em>initial velocity.</em><em> As an example, if you dropped a rock off a cliff, its </em><em>velocity</em><em> increases by 32 feet per second, every second.</em>
<em />
<h2><em>Hope this helps you a lot ...</em></h2><h2><em>Good day :)</em></h2>
Answer:
E
Explanation:
Planets after Mars in our solar system are called Jovian planets. Therefore, Jupiter, Saturn, Uranus and Neptune are Jovian planets. The specialty of these planets is that they mostly made of gases and have ring around them.
They have rings around them because tidal forces cause volcanic eruptions on some moons, and part of this material subsequently escaped the gravity of the moons, forming the rings.
Answer: The height above the release point is 2.96 meters.
Explanation:
The acceleration of the ball is the gravitational acceleration in the y axis.
A = (0, -9.8m/s^)
For the velocity we can integrate over time and get:
V(t) = (9.20m/s*cos(69°), -9.8m/s^2*t + 9.20m/s^2*sin(69°))
for the position we can integrate it again over time, but this time we do not have any integration constant because the initial position of the ball will be (0,0)
P(t) = (9.20*cos(69°)*t, -4.9m/s^2*t^2 + 9.20m/s^2*sin(69°)*t)
now, the time at wich the horizontal displacement is 4.22 m will be:
4.22m = 9.20*cos(69°)*t
t = (4.22/ 9.20*cos(69°)) = 1.28s
Now we evaluate the y-position in this time:
h = -4.9m/s^2*(1.28s)^2 + 9.20m/s^2*sin(69°)*1.28s = 2.96m
The height above the release point is 2.96 meters.
Missing question: "<span> What is the speed v of the bus?"</span>
Solution:
Let's solve the problem by writing the equilibrium conditions on both x- and y- axis:
where
is the weight of the lunch box,
is the centripetal force, T is the tension of the string and
.
The radius r is the one with respect to the vertical position of the string, therefore
.
From the first equation we find
and if we replace this into the second one, we find
from which we can find the velocity:
Answer:
The general equation for conservation of momentum during a collision between n number of objects is given as: [m i ×v i a ] = [m i ×v i b ] Where m i is the mass of object i , v i a is the velocity of object i before the collision, and v i b is the velocity of object i after the collision.
Explanation:
