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alexira [117]
3 years ago
15

What is the formula for conservation of momentum

Physics
1 answer:
olga55 [171]3 years ago
6 0

Answer:

The general equation for conservation of momentum during a collision between n number of objects is given as: [m i ×v i a ] = [m i ×v i b ] Where m i is the mass of object i , v i a is the velocity of object i before the collision, and v i b is the velocity of object i after the collision.

Explanation:

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5. It is the year 2085, and the world population has grown at an alarming rate. As a space explorer, you have been sent on a ter
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Answer:

Answer:

It has sunlight, oxygen, water, and fertile soil.

Explanation:

Sunlight: provides plants (producers) with energy so that the ecosystem is sustainable. Also provides heat and warmth so the planet does not freeze.  

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I will not write an entire description because your teacher may accuse you of plagiarism and use this topic as proof.

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You place the spring vertically with one end on the floor. You then lay a 1.60 kg book on top of the spring and release the book
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Answer:

Compression in the spring, x = 3.7 cm

Explanation:

It is given that,

Mass of the book, m = 1.6 kg

It can be assumed the spring constant of the spring is, k = 840 N/m

As the book moves down, the change in potential energy of the book is converted to spring potential energy of compression. The mathematical expression is as follows :

\dfrac{1}{2}kx^2=mgx

x=\dfrac{2mg}{k}

x=\dfrac{2\times 1.6\ kg\times 9.8\ m/s^2}{840\ N/m}  

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So, the spring is compressed to a distance of 3.7 cm. Hence, this is the required solution.

4 0
3 years ago
8. A 40.0kg block of metal is suspended from a scale and is immersed in water. The dimensions of the block are 12.0cm x 10.0cm x
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Answer:

a.1017.9N

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Explanation:

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Po=atmospheric pressure

g=gravity

h1=height

rh0=density of water

P1=Po+rho*g*h1

1.013*10^5+1000(9.81)(0.05)

1.0179*10^5Pa

at the level of the bottom of the block we have

P2=Po+rho*g*h2

1.013*10^5+1000(9.81)(0.17)

1.0297* 10^5 Pa

the downward force exerted on the top by the water is

Ftop=P*A== × = 1.0179* 10^5* 0.100

= 1017.9 N

and the upward force the water exerts on the bottom of the block , which is the buoyant force

Fbot== × = 1.0297 10^5 * 0.100 m

= 1029.7 N

(b) The scale reading is the tension, T, in the cord supporting the block.

if the block is at equilibrium, then sum of vertical forces

EFy=T+Fbot-Ftop-mg=0

T=mg+Ftop-Fbot

T=40*9.81-(1029.7-1017.9)

T=380.6N

(c)  Archimedes principle state that, the buoyant force on the block equals the weight of the displaced water. Thus,

Buoyant force=rho *g*h

= = 1000* 0.100^2 * 0.120 m *9.80 m s=11.8 N

from the answer a Ftop-Fbot

1029.7-1017.9=11.8N, the same as the buoyant force

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<em>A. A positive and negative charge attract each other.</em>

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