The equivalent formula for p = iv is the startfraction p over v endfraction = i
In physics, power measures the rate of transfer of electrical energy through a circuit per unit of time. It is denoted by P and is measured using the SI unit of power (watts or 1 joule/second). Electrical energy is usually supplied by batteries and produced by generators.
There are three types of power, true, reactive, and apparent, which are related in trigonometric form. This is called the power triangle. A power triangle that relates apparent power to active and reactive power. Power is measured in watts. One watt equals one joule per second.
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Answer:
See explanation
Explanation:
Since the original count rate is 600 Bq,
i) after 1 half life, the count rate decreases to 1/2 of 600 Bq = 300 Bq
ii) after 2 half lives, the count rate decreases to 1/4 of 600 = 150 Bq
iii) after 3 half lives, the count rate decreases to 1/6 of 600 = 100 Bq
iv) after 4 half lives, the count rate decreases to 1/8 of 600 = 75 Bq
Answer:
The total amount of CO₂ produced will be = 20680 kg/year
The reduction in the amount of CO₂ emissions by that household per year = 3102 kg/year
Explanation:
Given:
Power used by household = 14000 kWh
Fuel oil used = 3400 L
CO₂ produced of fuel oil = 3.2 kg/L
CO₂ produced of electricity = 0.70 kg/kWh
Now, the total amount of CO₂ produced will be = (14000 kWh × 0.70 kg/kWh) + (3400 L × 3.2 kg/L)
⇒ The total amount of CO₂ produced will be = 9800 + 10880 = 20680 kg/year
Now,
if the usage of electricity and fuel oil is reduced by 15%, the reduction in the amount of the CO₂ emission will be = 0.15 × 20680 kg/year = 3102 kg/year
Answer:
0.01774 lux
Explanation:
= Polarized light intensity = 36.8 lux
= Angle
Through first filter
Through second filter
intensity of transmitted light is 0.01774 lux
Answer:
y = -6.57 10⁻³ m
Explanation:
The movement of water is an oscillation in the vertical direction that can be approximated as a simple harmonic movement
y = A cos (wt)
where the amplitude is A = 0.75 m and the angular velocity is related to the frequency
w = 2π f
w = 2π 1.25
w = 7.85 rad / s
we substitute
y = 0.75 cos (7.85 t)
we look for the amplitude for a time of t = 2.20 s, remember that the angles are in radians
y = 0.75 cos (7.85 2.20)
y = -0.00657 m
y = -6.57 10⁻³ m
