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3 years ago

Jovian planets have rings because:__________.

Physics

1 answer:

soldier1979 [14.2K]3 years ago

7 0

Answer:

Explanation:

Planets after Mars in our solar system are called Jovian planets. Therefore, Jupiter, Saturn, Uranus and Neptune are Jovian planets. The specialty of these planets is that they mostly made of gases and have ring around them.

They have rings around them because tidal forces cause volcanic eruptions on some moons, and part of this material subsequently escaped the gravity of the moons, forming the rings.

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Refrigerators are usually kept at about 5∘C, while room temperature is about 20∘C. If you were to take an "empty" sealed 2-liter

expeople1 [14]

Answer:

The volume will not contract to one fourth of the original.

Explanation:

Applying Charles's Law as:

$\frac {V_1}{T_1}=\frac {V_2}{T_2}$

Given ,

V₁ = ?

V₂ = 2 L

T₁ = 5 °C

T₂ = 20 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (5 + 273.15) K = 278.15 K

T₂ = (20 + 273.15) K = 293.15 K

Using Charles law as:

$V_1=\frac {V_2}{T_2} \times {T_1}$

$V_1=\frac {2\ L}{293.15 K} \times {278.15 K}$

$V_1=1.8977 L$

Thus, the volume will not contract to one fourth of the original. (1/4 of 2 L is 0.5 L).

8 0

4 years ago

A thin oil slick (no=1.50) floats on water (nw=1.33). When a beam of white light strikes this film at normal incidence from air,

Sedbober [7]

Answer:

The (minimum) thickness of the oil slick is 325 nm.

Explanation:

Let the (minimum) thickness of the oil slick = $t_{o}$

Therefore:

2 $t_{o}$ = ( $m_{red}$ + $\frac{1}{2}$ )*λ $_{red}$ / $n_{o}$ (1)

similarly,

2 $t_{o}$ =( $m_{violet}+\frac{1}{2}$ )*λ $_{violet}$ / $n_{o}$ (2)

Thus, equation 1 = equation 2

( $m_{red}$ + $\frac{1}{2})$ *λ $_{red} /n_{o}$ = ( $m_{violet}+\frac{1}{2})$ *λ $_{violet}/n_{o}$

Where:

λ $_{red} = 650 nm$

λ $_{violet} = 390 nm$

$n_{o} = 1.5$

Therefore:

$\frac{2m_{violet}+1 }{2n_{red}+1 }$ =650/390=5/3

This shows that,

$m_{violet}$ =2

$m_{red}$ =1

Thus, using equation 2

$t_{o}$ = $\frac{5*390}{2*2*1.5} =325 nm$

6 0

3 years ago

A line on a speed-time graph with a steep slope indicates a greater speed? true or false

makvit [3.9K]

I think this is false
hope this helps...

5 0

3 years ago

If a girl is running along a straight road with a uniform velocity 1.5m/s find her acceleration

Jlenok [28]

Answer:

Dear user,

Answer to your query is provided below

Acceleration is zero because of no change in velocity.

Explanation:

Remember that velocity is a vector quantity and a vector can change in 3 ways

•Magnitude only

•Direction only

•Both magnitude and direction.

Now the magnitude of velocity (speed) can stay constant while the direction is changing. This is the case in circular motion.

In the question above, it is mentioned that the girl is moving along a straight road. Therefore no change in direction of velocity.

7 0

3 years ago

Someone please help. Describe how electric potential energy, kinetic energy, and work change when two charges of opposite sign a

erik [133]

Answer:

The answer is based on the conservation of energy law; something you should really understand by now.

For convenience we can hold one of the two charges still; it becomes the frame of reference. And everything we say is in reference to the designated static charge, call it Q.

So the moving charge, call it q, has total energy TE = PE. It's all potential energy as we start with q not moving.

It has potential energy because in order to separate q from Q, we had to do work, add energy, on q. And from the COE law, that work added is converted into PE.

It's a bit like lifting something off the ground. That's work and it becomes GPE. So there's some work, in separating the two charges in the first place.

But there's more.

Now we let q go. As opposites attract, q is pulled to Q. And that force from Q is working on q, force over distance. Which means the potential energy q started with is being converted into kinetic energy. q is accelerating and picking up speed.

And there's more work, done by the EMF on charge q. That converts the PE into KE and the q charge smashes into Q with some kinetic energy.

5 0

3 years ago