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AlekseyPX
3 years ago
15

Use the limit definition of derivative to determine whether the function f(z)=(\operatorname{Re} z)^{2}f(z)=(Rez) 2 is complex-d

ifferentiable anywhere it the complex plane (consider the vertical and horizontal limits for \Delta f / \Delta z,Δf/Δz, as we did in class). Is it analytic anywhere? Check your answer using Cauchy-Riemann equations, u_{x}=v_{y}, u_{y}=-v_{x}u x ​ =v y ​ ,u y ​ =−v x ​ .
Mathematics
1 answer:
beks73 [17]3 years ago
4 0
Hmmm 818291937739191 is the answer
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On a rectangle hyperbola, if one point is (2,3) and y varies inversely to x, find y when x is 6
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3 years ago
What is 123 round to the nearest hundered
irina1246 [14]
123 rounded to the nearest hundred is 100 i believe
8 0
3 years ago
Read 2 more answers
What is the radius of a Ø6.75" circle? 3.375" or 3.750" or 4.375" or 6.750"
zysi [14]

Answer:4.375

Step-by-step explanation:

4 0
2 years ago
What would the answer be?​
NikAS [45]

Answer:

11.35%  

Step-by-step explanation:

Add all of the numbers together to get the total amount of people who visited.

Add all the numbers in the teen section to find how many teens visited.

If you put teens over whole it will give you the fraction 86/758

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Move the decimal two places to the right and round to get the percent 11.35.

7 0
2 years ago
X squared+ y squared = 2 y = 2x squared – 3 Which of the following describes the system?
cluponka [151]

Answer:

x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

Step-by-step explanation:

I'm assuming the system is \left \{ {x^2+y^2=2} \atop {y=2x^2-3}} \right.:

x^2+y^2=2

x^2+(2x^2-3)^2=2

x^2+(4x^4-12x^2+9)=2

x^2+4x^4-12x^2+9=2

4x^4-11x^2+9=2

4x^4-11x^2+7=0

x^4-11x^2+28=0

(x^2-7)(x^2-4)=0

(4x^2-7)(x^2-1)=0

4x^2-7=0

4x^2=7

x^2=\frac{7}{4}

x=\pm\sqrt{\frac{7}{4}}

x^2-1=0

x^2=1

x=\pm1

y=2x^2-3

y=2(\pm\sqrt{\frac{7}{4}})^2-3

y=2({\frac{7}{4}})-3

y=\frac{7}{2}-3

y=\frac{1}{2}

y=2x^2-3

y=2(\pm1)^2-3

y=2(1)-3

y=2-3

y=-1

Therefore, x=-1,1,-\sqrt{\frac{7}{4} },\sqrt{\frac{7}{4}} and y=-1,\frac{1}{2}

The ordered pair solutions are (-\sqrt{\frac{7}{4}},0.5), (\sqrt{\frac{7}{4}},0.5), (-1,-1), and (1,-1).

4 0
2 years ago
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