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4 years ago

What is the surface area of the cube?

Mathematics

1 answer:

liraira [26]4 years ago

6 0

SA=6A2 so 6 times 49 squared is 294mmsquared

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Solve 15 x 14 <br> A. 200<br> B.120<br> C.225<br> D.210

GREYUIT [131]

The answer is D

Hope this helps!

5 0

3 years ago

Read 2 more answers

If a manufacturer conducted a survey among randomly selected target market households and wanted to be 95% confident that the d

katen-ka-za [31]

Answer:

We need a sample size of least 119

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Sample size needed

At least n, in which n is found when $M = 0.09$

We don't know the proportion, so we use $\pi = 0.5$ , which is when we would need the largest sample size.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.09 = 1.96\sqrt{\frac{0.5*0.5}{n}}$

$0.09\sqrt{n} = 1.96*0.5$

$\sqrt{n} = \frac{1.96*0.5}{0.09}$

$(\sqrt{n})^{2} = (\frac{1.96*0.5}{0.09})^{2}$

$n = 118.6$

Rounding up

We need a sample size of least 119

6 0

4 years ago

Kelly and Sean work together to clean a section of highway that is 10/3 Mile long. write this distance as a mixed number

skelet666 [1.2K]

3 1/3 easy i trick i use is too divide the three by 10 you get 3 and there's 1 left so three wholes and 1/3 left

5 0

3 years ago

Steven fill 3 pages in a stamp album. this is one sixth of the pages in the album. how many pages are there in steven stamp albu

Arturiano [62]

3 pages x 6 times=18 pages

7 0

4 years ago

A process produces a certain part with a mean diameter of 2 inches and a standard deviation of 0.05 inches. The lower and upper

Nimfa-mama [501]

Answer:

The value of Cp (measure of potential capability) is 6.33.

Step-by-step explanation:

Given information: Process average = 2 inches, process standard deviation = 0.05 inches, lower engineering specification limit = 1.6 inches and upper engineering specification limit =3.5 inches.

The formula for Cp (measure of potential capability) is

$CP=\frac{USL-LSL}{6\sigma}$