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3 years ago

6

Which ink spot had the most pigments? Question 3 options: black red blue green Which solvent caused the ink from the dots to mov

e the most? Question 4 options: half water, half alcohol alcohol vegetable oil water

1 answer:

GREYUIT [131]3 years ago

6 0

Answer:

The water/alcohol solvent caused the dots to move the most. The oil solvent

Explanation:

You might be interested in

How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?

xenn [34]

Answer:

$5.225x10^{22}atoms\ I$

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

$n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2$

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

$atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I$

Best regards!

4 0

3 years ago

Which statement correctly identifies the nuclide that is most likely to be unstable and describes why?

iVinArrow [24]

The answer would be B.

U-238 has a n to p ration of 1.6:1. 146 neutrons and 92 protons.

It is actually the most commonly used isotope is reactors.

C-14 is also a radioactive isotope with 8 neutrons and 6 protons.

The usual and ideal n to p ratio is 1:1 such as C-12 or Mg-24

8 0

3 years ago

How many moles in 110g of nahco3?

kenny6666 [7]

Hope this helps you.

5 0

3 years ago

How many of the following atomic particles does a neutral magnesium

VARVARA [1.3K]

Answer:

$\boxed{\text{12 p, 12 n, and 12 e}}$

Explanation:

No atoms of Mg have a mass of 24.3050 u. That is the average mass of all the isotopes of Mg.

However, the most common isotope of Mg is ₁₂²⁴Mg (mass = 23.99 u)

The atomic number of Mg is 12. It has 12 protons.

The atomic mass of ²⁴Mg is 24. That's the total number of protons and neutrons.

p + n = 24

12 + n = 24

n = 12

An atom of ²⁴Mg has 12 neutrons.

If the atom is neutral, the number of electrons equals the number of protons.

e = p = 12

$\text{An atom of }$^{24}$\text{Mg contains }\boxed{\textbf{12 p, 12 n, and 12 e}}$

3 0

3 years ago

How much heat is required to raise 36 g ice at – 10.0oC to steam at 110oC? (get your answers from question #1)

Gnom [1K]

Answer:

The total heat required to raise ice at -10°C to steam at 110°C = 91606.8 J

Explanation:

The heat involved in this process involves the following:

1. Heat to change ice at -10°C to ice at 0°C;

2. Heat to change ice at 0°C to water at 0°C

3. Heat to change water at 0°C to water at 100°C

4. Heat to change water at 100°C to steam at 100°C

5. Heat to change steam at 100°C to steam at 110°C

Specific heat capacity of ice, c = 2040 J/K/kg, Latent heat of fusion of ice, L = 3.35 × 10⁵ J/kg, specific heat capacity of water, c = 4182 J/K/kg, latent heat of vaporization of water, l = 2.26 × 10⁶ J/kg, specific heat capacity of steam, c = 1996 J/K/kg

Step 1: H = mcθ; where m = 30.0 g = 0.03 g, c = 2040 J/K/kg, θ = (0 - -10) = 10 K

H = 0.03 * 2040 * 10 = 612 J

Step 2: H = mL, where L = 3.35 × 10⁵ J/kg

H = 0.03 * 3.35 × 10⁵ = 10050 J

Step 3: H = mcθ, where c = 4182 J/K/kg, θ = (100 - 0) = 100 K

H = 0.03 * 4182 * 100 = 12546 J

Step 4: H = ml, where l = 2.26 × 10⁶

H = 0.03 * 2.26 × 10⁶ = 67800 J

Step 5: H = mcθ, where c = 1996 J/K/kg, θ = (110 - 100) = 10 K

H = 0.03 * 1996 * 10 = 598.8 J

Total heat required to raise ice at -10°C to steam at 110°C = (612 + 10050 + 12546 + 67800 + 598.8) J = 91606.8 J

Therefore, the total heat required to raise ice at -10°C to steam at 110°C = 91606.8 J

8 0

3 years ago