3 years ago

Calculate the solubility of silver chloride in 0.17M AgNO3. (Ksp=1.8E-10)

1 answer:

5 0

The dissociation equation is:

AgNO3 = Ag+ + NO3-

We write the Ksp expression.

Ksp = [Ag+] [NO3-]

Since there is 1:1 molar ratio, we can assign the two values at the right side with s which represents the molar solubility.

<span>1.8E^-10 = (s)(s)
</span><span>1.8E^-10 = s^2
</span>s=1.34 x 10^-5 M

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