Answer:
The pressure of N₂ gas in cylinder B when compressed at constant temperature increases due to the increase in the frequency of collision between the gas molecules with themselves and with the wall of their container caused by a decrease in volume of the container.
Explanation:
Gas helps to explain the behavior of gases when one or more of either temperature, volume or pressure is varying while the other variables are kept constant.
In the gas cylinder B, the temperature of the given mass of gas is kept constant, however, the volume is decreased by pushing the movable piston farther into the cylinder. According to the gas law by Robert Boyle, the volume of a given mass of gas is inversely proportional to its pressure at constant temperature. This increase in pressure is due to the increase in the frequency of collision between the gas molecules with themselves and with the wall of their container caused by a decrease in volume of the container. As the cylinder becomes smaller, the gas molecules which were spread out further become more packed closely together, therefore, their frequency of collision increases building up pressure in the process.
You can Multiply the whole equation with 2 as it is the denomanot number of 7/2.Therefore,the denomanator will be canceled out with 2 and the number of 7/2 will become 7.
Steps by Steps solution:
C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O
=2×(C3H8+7/2O2→3CO+4H2OC3H8+72O2→3CO+4H2O)
=2C3H8+7O2→6CO+8H2OC3H8+144O2→6CO+8H2O
The heat absorbed to raise temperature : Q = 31350 J
<h3>Further explanation
</h3>
Given
m = mass = 150 g
Δt = Temperature difference : 50 °C
Required
Heat absorbed
Solution
Heat can be formulated
<em>
Q = m.c.Δt
</em>
The specific heat of water = c = 4.18 J/g °C
Input the value :
Q = 150 x 4.18 x 50
Q = 31350 J
Smaller, there are many human and systematic errors that can alter the amount of product that can be obtained.
Answer and Explanation:
We need to remember the formulas:
- pOH = -log[OH-]
- pH = -log[H+]
- pH + pOH = 14
When given the concentration of OH-, denoted as [OH-], we can plug that value into the equation pOH = -log[OH-] to find the pOH. Once we have found the pOH, we can then subtract that value from 14 to determine the value of pH.
