Answer:
When cinnamic acid react with bromine ,addition reaction rapidly occur on alkene functional group to form dibromo product
Explanation:
Phenyl ring is an aromatic hydrocarbon ,when aromatic hydrocarbons react with Cl2,Br2 or KMnO4 no reaction occur ,where as unsaturated hydrocarbon like alkene react .Aromatic hydrocarbon with these reagents undenr different conditions undergoes subtituition reaction.They react with bromine in presence of lewis acid catalyst ferric bromide.
I'm taking this lesson now, so imma help u ( if u need anything else ask me)
so given Molar mass= 32 g/mol
molar mass= (empirical formula) n
32 = (14x1 + 2x1) n
32 = 16 n , so n= 2
so, molecular formula= N2H4
24.25 moles of NO can be produced using 97 moles of HNO3.
<h3>What is balanced chemical equation?</h3>
Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.
3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O
The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .
So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.
⇒ 8 HNO3⇔2 NO
⇒ 1 HNO3⇔ 1/4 NO
This means that for each mole of HNO3 produces 1/4 moles of NO.
So , for 97 moles of HNO3 ,
moles of NO can be made,
So, total moles of NO made are 24.25 moles.
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Answer:
covalent bond
Explanation:
The bond which is most common in the organic molecules is the covalent bond which involves sharing of the electrons between the two atoms.
Glycosidic bond, also known as glycosidic linkage is type of the covalent bond which joins carbohydrate molecule to other group that may not or may be a carbohydrate.
Glycosidic bond is the bond which is formed between hemiacetal or hemiketal group of the saccharide and hydroxyl group of compounds like alcohol.
Answer:
13.45 grams of NaCl will be produced
Explanation:
Given:
Mass of CuCl2 = 15 grams
Molar mass of CuCl2 = 134.5 g/mol
Mass of Na(NO3) = 20grams
Molar mass of Na(NO3) = 85 g/mol
To find:
Amount of Sodium chloride produced = ?
Solution:
<u>No of moles of CuCl2 = 15/134.5 = 0.11 moles</u>
<u>No of moles of Na(NO3) = </u><u>2</u><u>0</u><u>/</u><u>8</u><u>5</u><u> </u><u>=</u><u> </u><u>0.23 moles,</u>
<em><u>1CuCl2 + 2Na(NO3) --> 1Cu(NO3)2 + 2NaCl</u></em>
from the reaction, 1 mole of copper chloride reacts with 2 mole of NaNO3 to produce 2 moles of sodium chloride.
Hence, 0.11 mole of copper chloride will react with 0.23 mole of NaNO3 to produce 0.23 moles of sodium chloride.
Mass of 0.23 moles of NaCl = 0.23 × M.M of NaCl
<em><u>(Molar mass of NaCl = 58.5)</u></em>
Mass of 0.23 moles of NaCl = 0.23 × 58.5 = 13.45 grams
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