Answer:
The electrode that removes ions from solution
Explanation:
Each electrochemical cell consists of an anode and a cathode. Oxidation occurs at the anode and reduction occurs at the cathode.
At the anode, ions move from the electrode into the solution while at the cathode ions move from the solution to the electrode.
At the cathode, metal ions accept electron(s) and become deposited on the electrode hence this electrode removes ions from solution. This is reduction.
This is a synthesis reaction, where 2 reactants combine to form a single product.
In decomposition, 1 reactant splits into 2 products.
In single replacement, one element swaps with another, in the form A + BC = B + AC.
In double displacement two elements swap, in the form AB + CD = AD + CB
In neutralization (a kind of double displacement), an acid and a base react to form water and a salt.
Calculating for the moles of H+
1.0 L x (1.00 mole / 1 L ) = 1 mole H+
From the given balanced equation, we can use the stoichiometric ratio to solve for the moles of PbCO3:
1 mole H+ x (1 mole PbCO3 / 2 moles H+) = 0.5 moles PbCO3
Converting the moles of PbCO3 to grams using the molecular weight of PbCO3
0.5 moles PbCO3 x (267 g PbCO3 / 1 mole PbCO3) = 84.5 g PbCO3
Answer:
The material which is likely to slow the flow of electric charges the most is PVC plastic ‾ \text{\underline{PVC plastic}} PVC plastic.
Explanation:
brainlist please