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2 years ago

You have an allowance of $9 a week. Since you acted up in math class, your parents reduced your allowance by

Mathematics

2 answers:

liubo4ka [24]2 years ago

7 0

Answer:

13.5

Step-by-step explanation:

9 a week so they reduced it by 50% wich would be 4.5 then they add 50% do the math its 13.5

rewona [7]2 years ago

5 0

Hi dhcjgjnrn Sc can’t

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A survey of 2,000 doctor showed that an average of 3 out of 5 doctor use brand x aspirin. How many doctor use brand x asprin

choli [55]

3:5...added = 8

3/8(2000) = 6000/8 = 750 use brand x aspirin <===
5/8(2000) = 10000/8 = 1250 do not use brand x aspirin

4 0

3 years ago

Read 2 more answers

a random sample of 4 claims are selected from a lot of 12 that has 3 nonconforming units. using the hypergeometric distribution

Sloan [31]

Answer:

The probability that the sample will contain exactly 0 nonconforming units is P=0.25.

The probability that the sample will contain exactly 1 nonconforming units is P=0.51.

Step-by-step explanation:

We have a sample of size n=4, taken out of a lot of N=12 units, where K=3 are non-conforming units.

We can write the probability mass function as:

$P(x=k)=\frac{\binom{K}{k}\binom{N-K}{n-k}}{\binom{N}{n}}$

where k is the number of non-conforming units on the sample of n=4.

We can calculate the probability of getting no non-conforming units (k=0) as:

$P(x=0)=\frac{\binom{3}{0}\binom{9}{4}}{\binom{12}{4}}=\frac{1*126}{495}=\frac{126}{495} = 0.25$

We can calculate the probability of getting one non-conforming units (k=1) as:

$P(x=1)=\frac{\binom{3}{1}\binom{9}{3}}{\binom{12}{4}}=\frac{3*84}{495}=\frac{252}{495} = 0.51$

5 0

3 years ago

PLZ HELP ASAP BEFORE I GET IT WRONG!!!

lord [1]

A. $960.

B. $940?

c. Neither.

I hope thiss helped! I could be wrong, but I do believe A. and C. are correct.

5 0

3 years ago

The Office of Student Services at a large western state university maintains information on the study habits of its full-time st

Vera_Pavlovna [14]

Answer:

0.8254 = 82.54% probability that the mean of this sample is between 19.25 hours and 21.0 hours

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .