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muminat
3 years ago
14

Explain two ways to write 4/5 as a precent

Mathematics
1 answer:
Nimfa-mama [501]3 years ago
5 0
You can write as 0.45 or 0.00.45
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Use Lagrange multipliers to find the maximum and minimum values of
marusya05 [52]

The Lagrangian is

L(x,y,\lambda)=x+8y+\lambda(x^2+y^2-4)

It has critical points where the first order derivatives vanish:

L_x=1+2\lambda x=0\implies\lambda=-\dfrac1{2x}

L_y=8+2\lambda y=0\implies\lambda=-\dfrac4y

L_\lambda=x^2+y^2-4=0

From the first two equations we get

-\dfrac1{2x}=-\dfrac4y\implies y=8x

Then

x^2+y^2=65x^2=4\implies x=\pm\dfrac2{\sqrt{65}}\implies y=\pm\dfrac{16}{\sqrt{65}}

At these critical points, we have

f\left(\dfrac2{\sqrt{65}},\dfrac{16}{\sqrt{65}}\right)=2\sqrt{65}\approx16.125 (maximum)

f\left(-\dfrac2{\sqrt{65}},-\dfrac{16}{\sqrt{65}}\right)=-2\sqrt{65}\approx-16.125 (minimum)

5 0
3 years ago
Find the missing segment in the image below
makvit [3.9K]

Answer:

The missing segment length is 20.

Step-by-step explanation:

2 is multiplied by 4 to get to 8, so 5 must be multiplied by 4 to get to 20.

7 0
3 years ago
The area of a square is 50 meters. how long is each side? round your answer to the nearest meter.
DanielleElmas [232]
The closest would be 7
7x7 is 49 and that is the closest
8 0
3 years ago
Read 2 more answers
A semicircular archway is built in front of a garden using 8 congruent granite tiles, as shown in the diagram. Find the area of
lianna [129]
In your question that ask to calculate the area of one of the tiles if a semicircular archway in the front of the garden is using 8 congruent granite tiles and the area of one of the tiles is 2.9ft ^2. I hope you are satisfied with my answer and feel free to ask for more. 
5 0
3 years ago
The ratio of the length to the width of a rectangle is 5:4. The length of the rectangle is 60 inches. What is the width?
Firlakuza [10]

\huge\boxed{\text{48 inches}}

We know that \frac{\text{length}}{\text{width}} = \frac{60}{\text{width}} = \frac{5}{4}.

Solve using cross multiplication of the last two fractions. I will use w to represent the width of the rectangle. 60*4=w*5

Multiply. 240=5w

Divide both sides of the equation by 5. \boxed{48}=w

7 0
3 years ago
Read 2 more answers
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