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Ne4ueva [31]
3 years ago
15

Simplify without the absolute value |x+3| ; if x>2

Mathematics
1 answer:
inna [77]3 years ago
8 0

Answer:

x+3 if x>2

Step-by-step explanation:

Recall some following basic ideas about absolute value:

|0|=0 or I guess -(0)=0

|3|=3

|-3|=-(-3) or just 3 but there is a reason why I wrote it the way I did.

You see that the absolute value returned the same value if the value was positive.

You see that the absolute value returned the opposite value if the value was negative.

You can include 0 in either.

Let's look at |x+3| alone for a second.

*|x+3|=x+3 if x+3 is positive or zero.

When is x+3 positive or zero? [greater than or equal to 0]

x+3\ge 0

Subtract 3 on both sides

x\ge -3

*|x+3|=-(x+3) if x+3 is negative or zero.

When is x+3 negative or zero? [less or equal to 0]

x+3\le 0

Subtract 3 on both sides

x\le -3

So looking at the bullet points (the *), x>2 fits into the first inequality.

Therefore, |x+3|=x+3.

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Answer:

Step-by-step explanation:

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3 years ago
3x * (7 * x)<br><br> Solve each expression. Justify each step.
Natasha_Volkova [10]

Answer:

Use the distributive property.

3x(7*x) =

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4 years ago
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If 8% tax on a sale amounts to 96 cents,what is the final price(including tax) of the item?
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3 years ago
Set up the characteristic equation, which is given by r2 − 5r − 6 = 0. The roots of this equation are given by r1 = 6 and r2 = −
s344n2d4d5 [400]

Answer:

Step-by-step explanation:

From your characteristic equation, your recursive equation is

f(n+2) = 5 f(n=1) +6f(n)

the general solution:

f(n) = A6^n + B(-1)^n

The initial conditions are

f(0) =1 ~~~and~~~ f(1) = 3

For f(0) = 1, that is

f(0) = A6^0 + B(-1)^0 = A+ B=1 (*)

For f(1) = 3, that is

f(1) = A6^1 + B(-1)^1 = 3

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From (*) and (**) you solve for A and B

you have A = 4/7 and B= 3/7

Replace A, B into the general one, you have the particular solution for the given condition

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4 years ago
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