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amid [387]
3 years ago
5

A chemist combines ethane and chlorine with the goal of producing chloroethane which other product could be reasonably expected

to form
Chemistry
2 answers:
lesya692 [45]3 years ago
5 0
<span>So when the chemist combines Ethane (CH3CH3) and Chlorine (Cl2) with the intention of producing Chloroethane (CH3CH2Cl), the other product that's formed in this reaction is 1,2-dichloroethane (ClCH2CH2Cl) also called as Ethylene dichloride with molecular weight of 98.954 g/mol. This is a colorless oily flammable substance that weighs heaver when vaporized.</span>
morpeh [17]3 years ago
3 0

Answer: other products are 1,2-dichloroethane, 1,1-dichloroethane and 1,1,1-trichloro ethane formed.

Explanation: since in chlorination of Alkane is an example for free-radical Substitution and due to more reactivity of free-radical excess chlorination (poly chlorination) Occurs.

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a. What is the definition of a mole? b. What is the abbreviation for mole? SARM c. How many particles are in one mole? d. What n
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Mole is base unit of substance. The number of particles in one mole is equal to 6.022 × 10²³. The number of particle in a mole is called as Avogadro's number.

The mole of substance is the amount of substance that contain elementary particles as the number of atoms. the symbol of mole is mol. it is the SI unit of amount of substance. The number particles are ion one mole of substances is 6.022 × 10²³. The number of particles in one mole of substance is called as Avogadro's number.

Thus, Mole is base unit of substance. The number of particles in one mole is equal to 6.022 × 10²³. The number of particle in a mole is called as Avogadro's number.

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3 years ago
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Naturally occurring boron has an atomic mass of 10.810 amu consists of two isotopes. One of those isotopes is 10B with an isotop
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5 0
3 years ago
You have a graduated cylinder with 10 mL of water in it.
Law Incorporation [45]

Answer:

<h3>The answer is 10 g/mL</h3>

Explanation:

The density of a substance can be found by using the formula

density =  \frac{mass}{volume} \\

From the question

mass = 300 g

volume = final volume of water - initial volume of water

volume = 40 - 10 = 30 mL

We have

density =  \frac{300}{30}  =    \frac{30}{3}  \\

We have the final answer as

<h3>10 g/mL</h3>

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3 years ago
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