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amid [387]
3 years ago
5

A chemist combines ethane and chlorine with the goal of producing chloroethane which other product could be reasonably expected

to form
Chemistry
2 answers:
lesya692 [45]3 years ago
5 0
<span>So when the chemist combines Ethane (CH3CH3) and Chlorine (Cl2) with the intention of producing Chloroethane (CH3CH2Cl), the other product that's formed in this reaction is 1,2-dichloroethane (ClCH2CH2Cl) also called as Ethylene dichloride with molecular weight of 98.954 g/mol. This is a colorless oily flammable substance that weighs heaver when vaporized.</span>
morpeh [17]3 years ago
3 0

Answer: other products are 1,2-dichloroethane, 1,1-dichloroethane and 1,1,1-trichloro ethane formed.

Explanation: since in chlorination of Alkane is an example for free-radical Substitution and due to more reactivity of free-radical excess chlorination (poly chlorination) Occurs.

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During a reaction 24 cubic cm of carbon dioxide was given off. After 8 minutes no more gas was produced and the reaction was com
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Answer:

Explanation:

Given parameters:

Volume of CO₂ = 24cm³

time taken for the reaction to complete = 8minutes.

Unknown:

rate of reaction

Soution

The reaction rate is a measure of speed of a chemical reaction. It is often calculated using the expression below:

    Reaction rate = \frac{change in concentration of reactant/product}{time taken}

   Reaction rate = \frac{24}{8} = 3cm³/min

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3.0 kg of nitrogen gas in a piston cylinder device initially at a temperature of 300 K and a pressure of 100 kPa is compressed t
lutik1710 [3]

Answer:

ΔU = 103.54 KJ

Explanation:

∴ ΔU = Q + W

ideal gas:

∴ PV = nRT

∴ R = 8.314 L.KPa/K.mol

∴ n = 3000 g N2 * ( mol/28.0134g N2) = 107.143 mol N2

∴ m N2 = 3.0 Kg

∴ T1 = 300 K

∴ P1 = 100 KPa

∴ V1 = nRT1/P1 = 2672.36 L = 2.67 m³

⇒ V2 = 0.9*V1 = 2405.12 L = 2.41 m³

∴ P2 = 140 KPa

⇒ T2 = P2.V2/n.R = 377.99 ≅ 378 K

⇒ W = P1V1 - P2V2

⇒ W = ((100KPa)*(2.67m³)) - ((140KPa)*(2.41m³))

⇒ W = - 70.164 KJ

∴ Q = nCpΔT

∴ Cp = (5/2)*R = 20.785 J/mol.K ....ideal gas

⇒ Q = (107.143mol)*(20.785 J/mol.K)*(378 - 300)

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⇒ ΔU = 173.703 KJ - 70.164 KJ

⇒ ΔU = 103.54 KJ

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