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Neko [114]
2 years ago
15

A solution has a [H+] of 0.20 M. Find the pH of this solution.

Chemistry
1 answer:
Rus_ich [418]2 years ago
4 0

The pH of this solution : 0.699

<h3>Further explanation  </h3>

pH is the degree of acidity of a solution that depends on the concentration of H⁺ ions. The greater the value the more acidic the solution and the smaller the pH.  

pH = - log [H⁺]  

So that the two quantities between pH and [H⁺] are inversely proportional because they are associated with negative values.  

A solution whose value is different by n has a difference in the concentration of H⁺ ion of 10ⁿ.  

A solution has a [H+] of 0.20 M, so [H⁺]=0.2

\tt pH=-log[H^+]\\\\pH=-log[0.2]\\\\pH=1-log~2\\\\pH=0.699

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For example, whether light is wave or particle is matter of science.

Questions that cannot have a definite answer are the field of religion or philosophy, and are out of the boundaries of science.

For example, does a criminal deserve the punishment of not seeing light? It is a moral question, which to be responded needs the intervention of philosophy and that could have different anwers at different times and in different societies.

 


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3 years ago
Compare the wavelength and energy of ultraviolet rays to visible light
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3 years ago
When methane is completely combusted in oxygen forming carbon dioxide and
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2 years ago
Two different bromide solutions are mixed with each other: Solution 1 is an aqueous solution of 4.85 g aluminum bromidein 150. m
erma4kov [3.2K]

Answer:

M=0.380 M.

Explanation:

Hello there!

In this case, given those two solutions of aluminum bromide and zinc bromide, it is firstly necessary to compute the moles of bromide ions in each solution as shown below:

n_{Br^-}^{in\ AlBr_3}=4.85 gAlBr_3*\frac{1molAlBr_3}{266.69gAlBr_3}*\frac{3molBr^-}{1molAlBr_3}  =0.05456molBr^-\\\\n_{Br^-}^{in\ ZnBr_2}=7.75gZnBr_2*\frac{1molZnBr_2}{225.22gZnBr_2}*\frac{2molBr^-}{1molZnBr_2}  =0.06882molBr^-

Now, we compute the total moles of bromide:

n_{Br^-}=0.05456mol+0.06882mol\\\\n_{Br^-}=0.12338mol

Then, the total volume in liters:

150mL+175mL=325mL*\frac{1L}{1000mL} \\\\=0.325L

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M=\frac{0.12338mol}{0.325L}\\\\M=0.380M

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2 years ago
The conductance of the electric current through the electrolytic solution increases with
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The conductance of the electric current through the electrolytic solution increases with increase in concentration.

<h3>What is electrolytic solution?</h3>

Electrolytic solutions are solutions that are capable of conducting an electric current due to presence of ions.

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Increase in the concentration of the charges, increases the amount of charges in the solution and hence the conductance of the solutions will increase as well.

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