Answer:
D. a reactant that is catalyzed by an enzyme
Explanation:
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Answer : The correct option is, (b) +0.799 V
Solution :
The values of standard reduction electrode potential of the cell are:
![E^0_{[H^{+}/H_2]}=+0.00V](https://tex.z-dn.net/?f=E%5E0_%7B%5BH%5E%7B%2B%7D%2FH_2%5D%7D%3D%2B0.00V)
![E^0_{[Ag^{+}/Ag]}=+0.799V](https://tex.z-dn.net/?f=E%5E0_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D%3D%2B0.799V)
From the cell representation we conclude that, the hydrogen (H) undergoes oxidation by loss of electrons and thus act as anode. Silver (Ag) undergoes reduction by gain of electrons and thus act as cathode.
The half reaction will be:
Reaction at anode (oxidation) :
Reaction at cathode (reduction) :
The balanced cell reaction will be,

Now we have to calculate the standard electrode potential of the cell.

![E^o_{cell}=E^o_{[Ag^{+}/Ag]}-E^o_{[H^{+}/H_2]}](https://tex.z-dn.net/?f=E%5Eo_%7Bcell%7D%3DE%5Eo_%7B%5BAg%5E%7B%2B%7D%2FAg%5D%7D-E%5Eo_%7B%5BH%5E%7B%2B%7D%2FH_2%5D%7D)

Therefore, the standard cell potential will be +0.799 V
I would say d but I’m not sure
The noble gas is Xenon and its molar mass is 131 g/mol.
<h3>What is the molar mass of the noble gas?</h3>
The molar mass of the noble gas is determined as follows;
Let molar mass of unknown gas be M, and mass of gas be m
Density of the noble gas, ρ = 5.8 g/dm³
density = m/V
At STP;
- temperature, T = 273.15 K
- pressure, P = 1 atm
- molar gas constant, R = 0.0821 L.atmK⁻¹mol⁻¹
From ideal gas equation:
PV = nRT
where n = m/M
PV = mRT/M
M = mRT/PV
M = 0.0821 * 273.15 * 5.84/1
Molar mass of the noble gas = 131 g/mol
The noble gas is Xenon which has molar mass approximately equal to 131 g/mol.
Learn more about molar mass at: brainly.com/question/837939
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Answer:
4.52 x 10²⁴ atoms Cl
Explanation:
A mole is a name that means a certain number like a dozen means 12. 1 mole of chlorine atoms is 6.022 x 10²³ chlorine atoms. The unit conversion is 6.022 x 10²³/mol.

Round to 4.52 x 10²⁴ atoms Cl for the correct number significant figures.