Answer : The volume of
formed are 11.5 liters.
Explanation :
First we have to calculate the moles of ![CaCO_3](https://tex.z-dn.net/?f=CaCO_3)
![\text{Moles of }CaCO_3=\frac{\text{Mass of }CaCO_3}{\text{Molar mass of }CaCO_3}](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DCaCO_3%3D%5Cfrac%7B%5Ctext%7BMass%20of%20%7DCaCO_3%7D%7B%5Ctext%7BMolar%20mass%20of%20%7DCaCO_3%7D)
Molar mass of
= 100 g/mole
![\text{Moles of }CaCO_3=\frac{14.0g}{100g/mole}=0.14mole](https://tex.z-dn.net/?f=%5Ctext%7BMoles%20of%20%7DCaCO_3%3D%5Cfrac%7B14.0g%7D%7B100g%2Fmole%7D%3D0.14mole)
The balanced chemical reaction will be:
![CaCO_3\rightarrow CaO+CO_2](https://tex.z-dn.net/?f=CaCO_3%5Crightarrow%20CaO%2BCO_2)
From the balanced chemical reaction we conclude that,
As, 1 mole of
react to give 1 mole pf ![CO_2](https://tex.z-dn.net/?f=CO_2)
So, 0.14 mole of
react to give 0.14 mole pf ![CO_2](https://tex.z-dn.net/?f=CO_2)
Thus, the moles of
gas = 0.14 mole
Now we have to calculate the volume of
.
Using ideal gas equation:
![PV=nRT](https://tex.z-dn.net/?f=PV%3DnRT)
where,
P = pressure of gas = 1.00 atm
V = volume of gas = ?
T = temperature of gas = 1000 K
R = gas constant = 0.0821 L.atm/mole.K
n = moles of gas = 0.14 mole
Now put all the given values in the ideal gas equation, we get:
![(1.00atm)\times V=(0.14mole)\times (0.0821L.atm/mole.K)\times (1000K)](https://tex.z-dn.net/?f=%281.00atm%29%5Ctimes%20V%3D%280.14mole%29%5Ctimes%20%280.0821L.atm%2Fmole.K%29%5Ctimes%20%281000K%29)
![V=11.5L](https://tex.z-dn.net/?f=V%3D11.5L)
Therefore, the volume of
formed are 11.5 liters.