Answer:
f(x) = 3
y = 3
So from the graph the value of y = 3 is found D.
Thus x = -3.
All the best!
Answer:
210 m²
Step-by-step explanation:
The area of a rhombus is d₁ * d₂ * 0.5. In other words, the area is its diagonals multiplied together and divided by 2.
Substitute the measures of the diagonal given.
35 * 12 * 0.5 = 210
The area is 210 m²
I hope this helps! Feel free to ask any questions!
Why is (D₁ + D₂)/2 incorrect?
This is a really helpful link:
http://mathandmultimedia.com/2015/03/04/why-the-area-of-a-rhombus-half-the-product-of-its-diagonals/
https://byjus.com/maths/area-of-rhombus/
You need to make a draw of the problem to understand what to do.
The height of the pyramid, and half the original base side length make a rectangle triangle, whose hypothenuse is the height of the lateral area of one of the pyramids faces, so we have. So we use Pythagoras:
hyp^2 = 11^2 + 14^2 = 317
hyp = 17.8 m
that is the height of the lateral area triangle
Now to find the area of the lateral area triangle, we have:
a = base*height/2 = 22*17.8/2
a = 195.8 m^2
that is the lateral area of the pyramid, 196 m^2
Answer:
B.
Step-by-step explanation:
20-16= 4 (point increase)
4/16= 25%
25% increase.
It’s the 3rd or 4th one but I positive it’s 4th one