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Komok [63]
3 years ago
12

Which of the following is a force acting between objects that do not touch?

Physics
2 answers:
scoundrel [369]3 years ago
5 0

Answer:

the answer is

C.Electrical force

hope this helps u stay safe

Explanation:

kirill [66]3 years ago
3 0
The answer is B friction force
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What is the minimum diameter necessary for a radio telescope working at f=1×10^10 Hz to be able to separate two objects 1 deg ap
Ad libitum [116K]
Your answer is a yessssssir
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2 years ago
What vectors make up R
Tju [1.3M]

Strange as it may seem, I don't think ANY of those choices will work.  Anybody else ?

8 0
3 years ago
A student wish to measure the gravitational acceleration g. She does it by releasing a small lead ball from rest and measures th
Goryan [66]

Answer:

(9.64 +- 0.86) m/s^2

Explanation:

The generic motion equation for constant acceleration is

x = X0 + v0 * t + \frac{1}{2}*a * t^2

Where

X0: initial position

v0: initial speed

a: acceleration

t: time

If the object has an initial speed of zero, and the frame of reference is set conveniently so that the object initial position is zero, the equation simplifies to:

x = \frac{1}{2}*a * t^2

And the acceleration can be obtained as:

a = 2*\frac{x}{t^2}

Where x is the distance fallen and a = g.

So, with the data x = (100.0 +- 0.03) mm and t = (144 +- 3) ms we can calculate

g = 2*\frac{100}{144^2} = 9.64e-3 \frac{mm}{ms^2} = 9.64 \frac{m}{s^2}

For the uncertainty we have to calculate the relative uncertainties first

For the distance (100 * 0.3)/100 = 0.3%

For the time (100 * 3)/144 = 2.08%

For multiplications or divisions the relative uncertainties are added

0.3% + 2.08% + 2.08% = 4.46%

We convert this into absolute uncertainty:

(9.64e-3 * 4.46)/100 = 0.00043 mm/(ms^2)

Finally, this is multiplied by a constant scalar, so:

2 * 0.00043 mm/(ms^2) = 0.00086 mm/(ms^2)

We convert the units

0.86 m/(s^2)

And the measurement is (9.64 +- 0.86) m/s^2

A better method is putting the ball in a ramp instead of a free fall, that way the fall is longer and the effect of time measuring uncertainty is reduced.

5 0
3 years ago
What are examples of devices that use electromagnetic waves? Check all that apply.
yKpoI14uk [10]

Well, there aren't actually ANY that apply, because you haven't listed any.  But I've lived a long time, and I remember hearing about electromagnetic waves and things that use them, so I can list a FEW of them for you:

-- radios

-- TVs

-- garage-door openers

-- TV remotes

-- cell phones

-- smart phones

-- GPS

-- walkie-talkies

-- car headlights

-- lava lamps

-- toasters

-- LEDs

-- light bulbs

-- fluorescent light tubes

-- police radios

-- Doppler weather radars

-- CB radios

-- ham radios

-- neon signs

-- eyeglasses

-- microscopes

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-- gas stoves

-- electric stoves

-- wood stoves

-- microwave ovens

-- tanning beds

-- cameras

-- lasers

-- CD recorders and players

-- DVD recorders and players

-- Bluray recorders and players

-- movie cameras

-- movie projectors

-- reading lamps

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These are just the ones I can think of right now off the top of my head.  There are a lot of others.

5 0
3 years ago
Read 2 more answers
Explain an experiment of the phenomenon of rainfall​
maks197457 [2]

Unclear/incomplete question. However, I inferred you need an explanation of the phenomenon of rainfall​.

<u>Explanation</u>:

Basically, the phenomenon of rainfall​ follows a natural cycle called the water cycle. What we call <em>'rainfall'</em> occurs when water condensed (in liquid form) in the atmosphere is made to fall down on the ground as tiny droplets as a result of the forces of gravity.

<u>The water cycle makes rainfall possible:</u>

  • First, water on the earth's surface is evaporated (or is absorbed into) the atmosphere.
  • Next, it then condensed into liquid form; which later falls to the surface to the ground again. And the process continues.
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3 years ago
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