The set of two-digit primes is {11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97}
Of that list, the following primes are mirror images of each other
13 and 31
17 and 71
37 and 73
79 and 97
Note: we ignore 11 since 11 flips to 11 which is not distinct from its original
If you're looking for the largest prime of this form, then its 97
If you're looking for the largest gap, then subtract each pair
31-13 = 18
71-17 = 54
73-37 = 36
97-79 = 18
We see that 71 and 17 have the largest gap
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Answer:
Step-by-step explanation:
sin2x = 2sinx*cosx
=
* cosx
=
* cosx
= 2 
=
= 24/25
Answer:
Distribute, then combine like terms, subtract 10 from both sides of the equation, simplify, divide both sides of the equation by the same term, and simplify to get your solution.
Step-by-step explanation:
1.) Distribute
6−2(4−5)=40
6−8+10=40
2.) Combine like terms
6a-8a+10=40
-2a+10=40
3.) Subtract 10 from both sides of the equation
-2a+10=40
-2a+10-10=40-10
4.) Simplify
subtract the numbers
-2a+10-10=40-10
-2a=40-10
subtract the numbers
-2a=40-10
-2a=30
-2a=30
5.) Divide both sides of the equation by the same term
-2a=30

6.) Simplify
cancel terms that are in both the numerator or denominator

a=
Divide the numbers
a=
a=-15
a=-15
7.) Solution
a=-15
Complimentary angles, when added, = 90 degrees
so if one angle is x, then its compliment is 90 - x
x = 5(90 - x) - 6
x = 450 - 5x - 6
x + 5x = 450 - 6
6x = 444
x = 444/6
x = 74
and its compliment is : 90 - x.....90 - 74 = 16 <==