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3 years ago

How many electrons does a single hydrogen gain or lose in the following reaction? H 2 + O 2 → H 2 O

Chemistry

2 answers:

True [87]3 years ago

4 0

Answer:

Lose 1

Explanation:

Answer via Educere/ Founder's Education

wariber [46]3 years ago

3 0

Answer:

option B. Lose 1.

Explanation:

To determine the number of electrons that a single hydrogen gains or loses you need to realize that the chemical reaction is an oxidation-reduction (redox) reaction and state the changes in the oxidation states.

The substance that gains electrons is being reduced, reducing its oxidation number, and the substance that lose electrons is being oxidized, increasing its oxidation state.

1) State the oxidation state of hydrogen atoms in the rectant side:

H₂: the oxidation state of any element in its atomic or molecular form is zero. That is indicated as a superscript to the right of the chemical symbol: H₂⁰

2) State the oxidation state of the hydrogen atoms in the product side:

H₂O: the rule says that the oxidation state of oxygen, when combined with other elements, except in the case of peroxides, is -2.

Hence, in order to the molecule H₂O be neutral, the total charge contributed by the two atoms of hydrogen must be + 2: +2 - 2 = 0.

Since there are two hydrogen atoms, each contributes +2 / 2 = +1 charge.

3) Conclusion:

Every atom of hydrogen changes from a 0 oxidation number to a +1 oxidation number, which, in turn, means that every hydrogen atom loses one electron.

Thus, the answer is, the option B. Lose 1.

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3 years ago

For the following reaction, 38.3 grams of sulfuric acid are allowed to react with 33.5 grams of calcium hydroxide sulfuric acid(

Likurg_2 [28]

Answer:

What is the maximum amount of calcium sulfate that can be formed? 53.1 grams CaSO4

What is the FORMULA for the limiting reagent? H2SO4

What amount of the excess reagent remains after the reaction is complete? 4.59 grams of Ca(OH)2

Explanation:

Step 1: Data given

Mass of sulfuric acid = 38.3 grams

Molar mass of H2SO4 = 98.08 g/mol

Mass of calcium hydroxide = 33.5 grams

Molar mass of Ca(OH)2 = 74.09 g/mol

Step 2: The balanced equation

H2SO4 + Ca(OH)2 → CaSO4 + 2H2O

Step 3: Calculate moles of H2SO4

moles H2SO4 = mass H2SO4 / molar mass H2SO4

moles H2SO4 = 38.3 grams / 98.08 g/mol

moles H2SO4 = 0.390 moles

Step 4: Calculate moles of Ca(OH)2

moles Ca(OH)2 = 33.5 grams / 74.09 g/mol

moles Ca(OH)2 =0.452 moles

Step 5: Calculate limiting reactant

For 1 mol H2SO4, we need 1 mol of Ca(OH)2 to produce, 1 mol of CaSO4 and 2 mol of H2O

H2SO4 is the limiting reactant. It will completely be consumed (0.390 moles).

Ca(OH)2 is in excess. There will be consumed 0.390 moles

There will remain 0.452 - 0.390 = 0.062 moles

This is 0.062 * 74.09 g/mol = 4.59 grams

Step 6: Calculate moles of calcium sulfate

For 1 mol H2SO4, we need 1 mol of Ca(OH)2 to produce, 1 mol of CaSO4 and 2 mol of H2O

For 0.390 moles of H2SO4, there will be produced 0.390 moles of CaSO4

Step 7: Calculate mass of CaSO4

Mass CaSO4 = moles CaSO4 * molar mass CaSO4

Mass CaSO4 = 0.390 moles * 136.14 g/mol

Mass of CaSO4 = 53.1 grams

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2 years ago