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3 years ago

How many electrons does a single hydrogen gain or lose in the following reaction? H 2 + O 2 → H 2 O

Chemistry

2 answers:

True [87]3 years ago

4 0

Answer:

Lose 1

Explanation:

Answer via Educere/ Founder's Education

wariber [46]3 years ago

3 0

Answer:

option B. Lose 1.

Explanation:

To determine the number of electrons that a single hydrogen gains or loses you need to realize that the chemical reaction is an oxidation-reduction (redox) reaction and state the changes in the oxidation states.

The substance that gains electrons is being reduced, reducing its oxidation number, and the substance that lose electrons is being oxidized, increasing its oxidation state.

1) State the oxidation state of hydrogen atoms in the rectant side:

H₂: the oxidation state of any element in its atomic or molecular form is zero. That is indicated as a superscript to the right of the chemical symbol: H₂⁰

2) State the oxidation state of the hydrogen atoms in the product side:

H₂O: the rule says that the oxidation state of oxygen, when combined with other elements, except in the case of peroxides, is -2.

Hence, in order to the molecule H₂O be neutral, the total charge contributed by the two atoms of hydrogen must be + 2: +2 - 2 = 0.

Since there are two hydrogen atoms, each contributes +2 / 2 = +1 charge.

3) Conclusion:

Every atom of hydrogen changes from a 0 oxidation number to a +1 oxidation number, which, in turn, means that every hydrogen atom loses one electron.

Thus, the answer is, the option B. Lose 1.

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cricket20 [7]

Answer:

746 Watt

Explanation:

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3 years ago

What is indicated by the prop-prefix?

Vikentia [17]

The prop prefix indicates that in the molecule, we have an arrangement of 3 carbon atoms.

<h3>What is a prefix in organic chemistry?</h3>

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2 years ago

An antifreeze solution is made by mixing ethylene glycol (ρ = 1116 kg/m3) with water. suppose the specific gravity of such a sol

Harman [31]

Answer is: the volume percentage of ethylene glycol in the solution is 43.1%.
V(solution) = 1 m³.
d(solution) = 1050 kg/m³.
m(solution) = 1050 kg.
d(ethylene glycol) = 1116 kg/m³.
d(water) = 1000 kg/m³.
m(solution) = d(ethylene glycol) · V(ethylene glycol) + d(water) · V(water).
V(ethylene glycol) = 1m³ - V(water).
1050 kg = 1116 kg/m³ · (1m³ - V(water)) + 1000 kg/m³ · V(water).
1050 kg = 1116 kg - 1116·V(water) + 1000·V(water).
116 kg/m³ ·V(water) = 66kg.
V(water) = 0.569 m³.
V(ethylene glycol) = 1 m³ - 0.569 m³ = 0.431 m³.
percentage = 0.431 m³ ÷ 1 m³ · 100% = 43.1%.

3 0

3 years ago

The reaction 2NO(g) + O2(g) → 2NO2(g) is a synthesis reaction. True False

Trava [24]

true

not sure though

but I think

7 0

3 years ago

Read 2 more answers

Limiting Reactant

liraira [26]

Answer:

(1) Cl₂ is the limiting reactant.

(2) 8.18 g

Explanation:

2Na(s) + Cl₂(g) → 2NaCl(s)

First we convert the given masses of reactants into moles, using their respective molar masses:

Na ⇒ 12.0 g ÷ 23 g/mol = 0.522 mol Na

Cl₂ ⇒ 5.00 g ÷ 70.9 g/mol = 0.070 mol Cl₂

0.070 moles of Cl₂ would react completely with (2 * 0.070) 0.14 moles of Na. There are more Na moles than that, so Na is the reactant in excess while Cl₂ is the limiting reactant.

Then we calculate how many moles of NaCl are formed, using the limiting reactant:

0.070 mol Cl₂ * $\frac{2molNaCl}{1molCl_2}$ = 0.14 mol NaCl

Finally we convert NaCl moles into grams:

0.14 mol NaCl * 58.44 g/mol = 8.18 g

3 0

3 years ago