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3 years ago

How adding tin to copper makes the bronze alloy harder?

Chemistry

2 answers:

andrey2020 [161]3 years ago

8 0

It makes the bronze stronger and harder than either of the other two medals

nika2105 [10]3 years ago

4 0

The molecules are different sizes so they can’t move past each other in the structure.

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Can someone please help I need help?!?!

anzhelika [568]

Answer:

a: 6 moles

b: 6.75 moles

c: 5 grams

Explanation:

a: mole ratio 2:3

b: mole ratio 2:3

c: mole ratio 2:2

7 0

3 years ago

Value 1: 45.58g

Rama09 [41]

Answer:

<h2>Percentage error is a measurement of the discrepancy between an observed and a true, or accepted value .</h2>

Explanation:

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7 0

3 years ago

Which statement correctly describes the actual yield and the theoretical yield of a reaction? (1 point)

Furkat [3]

Answer:

C: The actual yield depends on the reaction conditions, but the theoretical yield varies only with reactant amounts

Explanation:

Looking at the options, the correct one is Option C because the actual yield usually depends on the conditions of the reaction, while the theoretical yield usually varies with only the amount of reactant.

8 0

2 years ago

Given the following information, what is the concentration of H2O(g) at equilibrium? [H2S](eq) = 0.671 M [O2](eq) = 0.587 M Kc =

MAVERICK [17]

<u>Answer:</u> The equilibrium concentration of water is 0.597 M

<u>Explanation:</u>

Equilibrium constant in terms of concentration is defined as the ratio of concentration of products to the concentration of reactants each raised to the power their stoichiometric ratios. It is expressed as $K_{c}$

For a general chemical reaction:

$aA+bB\rightleftharpoons cC+dD$

The expression for $K_{eq}$ is written as:

$K_{c}=\frac{[C]^c[D]^d}{[A]^a[B]^b}$

The concentration of pure solids and pure liquids are taken as 1 in the expression.

For the given chemical reaction:

$2H_2S(g)+O_2(g)\rightleftharpoons 2S(s)+2H_2O(g)$

The expression of $K_c$ for above equation is:

$K_c=\frac{[H_2O]^2}{[H_2S]^2\times [O_2]}$

We are given:

$[H_2S]_{eq}=0.671M$

$[O_2]_{eq}=0.587M$

$K_c=1.35$

Putting values in above expression, we get:

$1.35=\frac{[H_2O]^2}{(0.671)^2\times 0.587}$

$[H_2O]=\sqrt{(1.35\times 0.671\times 0.671\times 0.587)}=0.597M$

Hence, the equilibrium concentration of water is 0.597 M

8 0

3 years ago

Why should you clean up after every investigation

8_murik_8 [283]

You should clean up after every investigation because if you leave a mess, maybe another detective will come in and get lost because of the mess you left.

6 0

4 years ago

Read 2 more answers