The graph of this projectile is a parabola. The tome to reach maximum height can be found using the formula t=-b/2a, where b is the linear term's coefficient and a is the quadratic term's coefficient. Plugging in the values for b and a, we arrive at t=-576/-32=18 seconds.
Since an application is 2/7 grams.
Number of applications = 34 ÷ 2/7
= 34 × 7/2
= 17 × 7
= 119
Number of applications = 119
Answer:
The correct answer is two triangles.
Step-by-step explanation:
In ▲ABC, a = 48.6, c = 41.7, C = 23°
.
Thus this information gives two distinct triangles.
The first triangle is an acute triangle in quadrant 1. The angle measures of this triangle are ∠A = 27.09° and ∠B = 129.91°. The lengths of the sides of this triangle are a = 48.6; b = 81.86; c = 41.7.
The second triangle is an obtuse triangle in quadrant 2. The angle measures of the other triangle are ∠A = 152.91° and ∠B = 4.09°. The lengths of the sides of this triangle are a = 48.6; b = 7.61 ; c = 41.7.
Answer:
14.99
Step-by-step explanation:
20.02=50-2t
20.02-50= -2t
-29.98= -2t