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grandymaker [24]
3 years ago
15

Perform the indicated math on the two vectors: (23, 13) minus (34∠-37°)

Physics
2 answers:
Greeley [361]3 years ago
6 0

The vector (34, <-37) has horizontal and vertical components.

The horizontal component adds to the x-component of the first
vector, and the vertical component adds to the y-component of
the first vector.

The horizontal component of (34, <-37) is  34cos(-37)  =  27.15

The vertical component of  (34,  <-37) is  34sin(-37)  =  -20.46

The sum of the two horizontal components is (23 + 27.15)  = 50.15 

The sum of the two vertical components is  (13 - 20.46) =  -7.46 .

The sum of the two vectors is the vector   (50.15,  -7.46) . 
vovikov84 [41]3 years ago
3 0
(23-34,13--37)
(-11,13-37)
(-11,50)
Hope that helps
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NARA [144]

As per the question the initial speed of the car [ u] is 42 m/s.

The car applied its brake and comes to rest after 5.5 second.

The final velocity [v] of the car will be zero.

From the equation of kinematics we know that

                                         v=u+at [ here a stands for acceleration]

                                         0=42 +5.5a

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Here a is taken negative as it the car is decelerating uniformly.

We are asked to calculate the stopping distance .

From equation of kinematics we know that

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The age of the universe is determined by the pace of expansion in the past, and each model forecasts a different pace.

This is due to the fact that the expansion rate in the coasting model is constant and never changes. Because the cosmos is growing faster now than during the old days, recollapsing and critical models give shorter ages. According to the accelerating model, the universe is growing at a slower rate currently than in the past, implying an older age.

4 0
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Two engineering students, John with a weight of 96 kg and Mary with a weight of 48 kg, are 30 m apart. Suppose each has a 0.04%
djyliett [7]

Answer:

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Z = Atomic number of water = 18

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m = Mass of person

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n=\dfrac{mN_AZe}{M}

q=imbalance\times \dfrac{mN_AZe}{M}

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Answer:

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W=(2000 N)(30 m)=60,000 J

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