Answer:
Acceleration of the bullet will be 1778835.6 
Explanation:
We have given length of the barrel refile s= 0.855 m
When the bullet leaves the muzzle its velocity is 553 m/sec
So final velocity v = 553 m/sec
Initial velocity will be 0 that is u = 0 m/sec
According to third equation of motion 
Answer: 245 meters
Explanation: 49 ? Meters
over over over
1 5 seconds
Cross multiply- 49 times 5 divided by 1 which equals 245
Answer:
<h2>workdone = force × distance </h2><h2>236J = 18.9cos(o) × 24.4</h2><h2>236/24.4 = 18.9cos(o)</h2><h2>(0.5117)cos^-1 = (o)</h2><h2><u>59.21°</u></h2>
Answer:
(a) They must have same direction
(b) It is not necessary for them to have same magnitudes
Explanation:
(a)
Momentum is a vector quantity. It is the product of mass (scalar) and velocity (vector). Thus, if the direction of velocity is changed, then as a result the direction of momentum will also change or its magnitude or component in the same direction will change. Hence, for the two objects to have same momentum, the directions of their velocities must also be the same.
(b)
Since, the momentum is product of velocity and mass. It is possible that two bodies of different masses with different velocities might have same momentum, provided the direction of their velocities is same.
For example, take a body of mass 4 kg moving with speed 5 m/s. It will have a momentum of 20 N.s. Now, consider another body of mass 2 kg, moving with speed 10 m/s. It will also have a momentum of 20 N.s.
Thus, it is not necessary for two objects to have same magnitude of velocity to have same momentum.
Answer:
Length of pipe 
meter
Explanation:
Speed of a transverse wave on a string
where F is the tension in string and 
is the mass per unit length
Thus,
Substituting the given values we get -
Speed of a transverse wave on a string
For third harmonic wave , frequency is equal to
Substituting the given values, we get -
Length of pipe
Substituting the given values we get
for first harmonic wave
Length of pipe meter
