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kupik [55]
3 years ago
10

In circle A, ∠BAE ≅ ∠DAE.

Mathematics
2 answers:
liraira [26]3 years ago
6 0

Answer:

x = 17

Step-by-step explanation:

:) I hope you have a good day

kirza4 [7]3 years ago
5 0

The image of circle A is missing, so i have attached it;

Answer:

x = 17

Step-by-step explanation:

In Δs EAB and EAD

We are told that;

∠BAE ≅ ∠DAE

AB = AD = AE

Now,

The Two triangles have two corresponding equal sides and the angles between them are equal, thus, we can say that the two triangles are congruent by SAS (Side Angle Side) postulate of congruence

By using the result of congruence, we can say that;

EB ≅ ED

We are given that;

EB = 3x - 24 and ED = x + 10

Thus,

3x - 24 = x + 10

∴ 3 x - 24 = x + 10

Add 24 to both sides to give;

3x = x + 34

Subtract x from both sides to give;

2x = 34

Divide both sides by 2 to give;

x = 17

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Marina86 [1]

Step 1 ) Move all terms right side of the equation.

\displaystyle\ x^{2} + 6x = -18

\displaystyle\ x^{2} + 6x + 18 = -18 + 18

\displaystyle\ x^{2} +6x + 18 = 0

Step 2 ) Apply quadratic formula. (Note: There are 2 solutions)

\displaystyle\ x^{2} +6x + 18 = 0

\displaystyle\ x = \frac{-b\sqrt{b^{2}-4ac}}{2a}, \displaystyle\ x = \frac{-b-\sqrt{b^{2}-4ac}}{2a}

\displaystyle\ x = \frac{-6+\sqrt{6^{2}-4 * 18}}{2} , \displaystyle\ x = \frac{-6-\sqrt{6^{2}-4*18}}{2}

\displaystyle\ x = \frac{-6+6i}{2} ,

\displaystyle\ x = \frac{-6-6i}{2}

Step 3 ) Simplify.

\displaystyle\ x = \frac{-6+6i}{2} ,

\displaystyle\ x = \frac{-6-6i}{2}

\displaystyle\ x = -3+ 3i,

\displaystyle\ x = -3 - 3i

Since the options only provide one of the answer we found, the answer is...

\displaystyle\ x = -3 - 3i

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- <em>Marlon Nunez</em>

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Step-by-step explanation:

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1/(6\sqrt{7} -1)\\ (6\sqrt{7}+1)/((6\sqrt{7} - 1)(6\sqrt{7} + 1))\\ (6\sqrt{7}+1)/((6\sqrt{7})^2 + 6\sqrt{7} - 7\sqrt{7} - 1)\\(6\sqrt{7}+1)/((6\sqrt{7})^2 - 1)\\(6\sqrt{7}+1)/((36*7 - 1)\\(6\sqrt{7}+1)/251

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