Answer:
15.01 Liters
Explanation:
T₁ = Initial temperature = 25°C = 298.15 K
T₂ = Final temperature = 100°C = 373.15 K
V₁ = Initial volume = 12 mL
Here, pressure is constant so we apply Charles Law
∴ Final volume at 100°C is 15.01 Liters.
(a) Check all of the following that are correct statements, where E stands for γmc2. Read each statement very carefully to make
sure that it is exactly correct.
The definition K = E - mc2 is valid even for speeds near the speed of light.
The energy principle can be written Esys,f = Esys,i + Wsurr.
The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.
At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.
The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.
The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.
The energy principle can be written deltaEsys = Wsurr.
(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?
The definition K = E - mc2 is valid even for speeds near the speed of light.
The energy principle can be written Esys,f = Esys,i + Wsurr.
The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.
At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.
The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.
The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.
The energy principle can be written deltaEsys = Wsurr.
(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?
1 answer:
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Answer:
The beach ball's velocity at the moment it was tossed into the air is <u>4.9 m/s.</u>
Explanation:
Given:
Time taken by the ball to reach maximum height is,
We know that, velocity of an object at the highest point is always zero. So, final velocity of the ball is,
Also, acceleration acting on the ball is always due to gravity. So, acceleration of the ball is,
The negative sign is used as acceleration is a vector and it acts in the downward direction.
Now, we have the equation of motion relating initial velocity, final velocity, acceleration and time given as:
Where, 'u' is the initial velocity.
Plug in the given values and solve for 'u'. This gives,
Therefore, the beach ball's velocity at the moment it was tossed into the air is 4.9 m/s