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saveliy_v [14]
3 years ago
14

(a) Check all of the following that are correct statements, where E stands for γmc2. Read each statement very carefully to make

sure that it is exactly correct.
The definition K = E - mc2 is valid even for speeds near the speed of light.

The energy principle can be written Esys,f = Esys,i + Wsurr.

The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.

At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.

The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.

The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.

The energy principle can be written deltaEsys = Wsurr.

(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?

Physics
1 answer:
Reil [10]3 years ago
5 0

Answer:

V=9.60m/s

Attached is the solution

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7 0
3 years ago
Solve ~<br><img src="https://tex.z-dn.net/?f=13x%20-%2026%20%2B%2039%20%3D%200" id="TexFormula1" title="13x - 26 + 39 = 0" alt="
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Explanation:

13x - 26 + 39 = 0

13x=26-39

13x=-13

x= -1

4 0
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