(a) Check all of the following that are correct statements, where E stands for γmc2. Read each statement very carefully to make
sure that it is exactly correct.
The definition K = E - mc2 is valid even for speeds near the speed of light.
The energy principle can be written Esys,f = Esys,i + Wsurr.
The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.
At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.
The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.
The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.
The energy principle can be written deltaEsys = Wsurr.
(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?
The definition K = E - mc2 is valid even for speeds near the speed of light.
The energy principle can be written Esys,f = Esys,i + Wsurr.
The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.
At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.
The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.
The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.
The energy principle can be written deltaEsys = Wsurr.
(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?
1 answer:
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Answer:
a) Tc = 750 [N] ;b) See the explanation below.
Explanation:
To solve this problem, we first need a graphical explanation of this, as well as knowing the corresponding questions. Therefore, a search was carried out in google, in the attached image we will find a graphical description of the problem.
b)
The solution of this type of problem corresponds to the use of Newton's third law, applying static which tells us that the sum of the forces in a system in equilibrium without movement must be equal to zero.
a)
In this way we can find by means of a sum of forces on the y axis equal to zero:
- 850 - 450 + 550 + Tc = 0
Tc = 750 [N]
