(a) Check all of the following that are correct statements, where E stands for γmc2. Read each statement very carefully to make
sure that it is exactly correct.
The definition K = E - mc2 is valid even for speeds near the speed of light.
The energy principle can be written Esys,f = Esys,i + Wsurr.
The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.
At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.
The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.
The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.
The energy principle can be written deltaEsys = Wsurr.
(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?
The definition K = E - mc2 is valid even for speeds near the speed of light.
The energy principle can be written Esys,f = Esys,i + Wsurr.
The definition of work is W = Fxdeltax + Fydeltay + Fzdeltaz.
At speeds close to the speed of light, kinetic energy is approximately equal to (1/2)mv2.
The definition of work is W = < Fxdeltax, Fydeltay, Fzdeltaz >.
The definition of work is W = |< Fxdeltax, Fydeltay, Fzdeltaz >|.
The energy principle can be written deltaEsys = Wsurr.
(b) An object with mass 70 kg moved in outer space. When it was at location < 14, -32, -7 > its speed was 11.5 m/s. A single constant force < 240, 400, -120 > N acted on the object while the object moved to location < 19, -40, -12 > m. What is the speed of the object at this final location?
1 answer:
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The tension in the supporting cable when the cab originally moves downward is 18422.4 N
What is tension?
Tension is described as the pulling force by the means of a three-dimensional object.
Tension might also be described as the action-reaction pair of forces acting at each end of said elements.
Here,
m =combined mass = 1600 kg
s = Displacement of the elevator = 42 m
g = Acceleration due to gravity = 9.81 m/s²
u = Initial velocity = 12 m/s
v = Final velocity = 0
According to the equation of motion:
0 - 12^2 = 2*a*42
a = - 144 / 84
a = - 1.714 m/s^2
Now let's write the equation of the forces acting on the elevator. Taking upward as positive direction:
T-mg = ma
T = m(g-a)
T = 1600 ( 9.8-(-1.74))
T=18422.4 N
Hence,
The tension in the supporting cable when the cab, originally moving downward is 18422.4 N
Learn more about tension here:
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