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2 years ago

5

A graph here shows the displacement of an adult that left their house, realized that they forgot to lock the door, and then retu

rned home to secure the lock. Interpret the graph and select the statements that are supported by the information here. Select ALL that apply.
A) The total displacement is zero.
B) The person walked more quickly to return home.
C) The walker turned began to return home at 6 seconds.
D) The person turned around to return home at 11 seconds.
E) The person paused to think about if they locked the door between 6 and 11 seconds

1 answer:

Effectus [21]2 years ago

8 0

the person paused to think about if they locked the door between 6 and 11 seconds

the person turned around to return home at 6 seconds

the total displacement is 0

Explanation:

i took the test

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Answer:

$1\cdot 10^{-8} N$ to the left

Explanation:

The magnitude of the electrostatic force between two charges is given by the following equation:

$F=k\frac{q_1 q_2}{r^2}$

where:

$k=9\cdot 10^9 Nm^{-2}C^{-2}$ is the Coulomb's constant

$q_1, q_2$ are the magnitude of the two charges

r is the distance between the two charges

Moreover, the force is:

- Attractive if the charges have opposite sign

- Repulsive if the charges have same sign

In this problem, we have:

$q_1=2nC=2\cdot 10^{-9}C$ is the magnitude of charge 1

$q_2=5nC =5\cdot 10^{-9}C$ is the magnitude of charge 2

r = 3 m is the distance between the two charges

Substituting, we find the force on both charges:

$F=\frac{(9\cdot 10^9)(5\cdot 10^{-9})(2\cdot 10^{-9}}{3^2}=1\cdot 10^{-8} N$

Here, the two charges are both positive, so the force is repulsive; since the 2 nC charge is on the left, this means that the force on this charge is to the left (away from the 5 nC charge).

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3 years ago

The current illustrated in the diagram is directed upward in a straight vertical wire. A compass is placed alongside the wire at

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<span>here we have to apply the right hand rule no, since the magnetic field is perpendicular with respect to the direction of the current</span>

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3 years ago

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Answer:

7.0N

Explanation:

F=ma

v2=u2+2as

25=0+20a

a=1.25m/s2

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3 years ago

A 5.30 g bullet moving at 963 m/s strikes a 610 g wooden block at rest on a frictionless surface. The bullet emerges, traveling

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Answer:

a) $V_{wf}$ = 4.67m/s

b) V = 8.29 m/s

Explanation:

Givens:

The bullet is 5.30g moving at 963m/s and its speed reduced to 426m/s. The wooden block is 610g.

a) From conservation of linear momentum

Pi = Pf

$m_{b}V{b_{i} } + V_{wi} = m_{w} V_{wf} + m_{b}V_{bf}$

where $m_{b},V{b_{i}$ are the mass and the initial velocity of the bullet, $m_{w}$ and $V_{wi}$ are the mass and the initial velocity of the wooden block, and $V_{wf}$ and $V_{bf}$ are the final velocities of the wooden block and the bullet

The wooden block is initial at rest $(V_{wi} = 0)$ this yields

$m_{b}V{b_{i} } = m_{w} V_{wf} + m_{b}V_{bf}$

By solving for $V_{wf}$ adn substitute the givens

$V_{wf}$ = $\frac{m_{b}V_{bi} - m_{b} V_{bf} }{m_{W} }$

= $\frac{5.3(g)(963(m/s)-426(m/s) }{610(g)}$

$V_{wf}$ = 4.67m/s

b) The center of mass speed is defined as

$V = \frac{m_{b} }{m_{b}+m_{w} } V_{bi}$

substituting:

$V = \frac{5.3(g)}{5.3(g)+610(g)} X 963(m/s)$

V = 8.29 m/s

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3 years ago

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notka56 [123]

Answer:

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Explanation:

From the question we are told

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Substituting for $I_1$ and $\theta _1$

$I_2 = \frac{I_o}{2} cos^2 (45)$

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$I_3 = \frac{I_o}{4} cos ^2 (90 - 45)$

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3 years ago