Answer:
a) 425.6 K = 152.6 degree Celsius
b) 678.6 square centimeter
Explanation:
Initial enthalpy = Final enthalpy
m(h1 + v1^2/2) = m(h2 + v2^2/2)
(h1 + v1^2/2) = (h2 + v2^2/2)
h 2 = (h1 + v1^2/2) - (v2^2/2)
h 2 = 400.98 + (230^2 – 30^2)/2 * 10^-3
= 426.98 KJ/Kg
T2 = T1’ + (T2’ -T1’)(h2-h1’)/( h2’-h1’)
T2 = 420 + (430-420)(431.43-421.26)(426.98-421.26)/(431.43 – 421.26)
T2 = 425.6 K = 152.6 degree Celsius
Area = mRT2/P2V2
Area = (600/60*60*1) *0.287*425.6/(100*30) *10^4
Area = 678.6 square centimeter
Answer:
a. E=8.97*10^{-21} J
b. v-He2 = 1.161 km/s
v-Ar2 = 369.74 m/s
Explanation:
(a) The average kinetic energy is given by
where KB is the Boltzman's constant and T is the temperature. For each molecule we have:
is the same for both type of molecules because is independent of the mass
(b)
where R is the constant of ideal gases, and M is the mass of the molecule. BY replacing for each type of molecule we obtain:
v-He2 = 1.161 km/s
v-Ar2 = 369.74 m/s
hope this helps!!
A blue sign? that that says what is on that exit. like nearby rest area, gas station, fast food, hotel, etc
Answer:
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Explanation:
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Answer:
so height is 0.1283 m
Explanation:
given data
height = 28 cm
diameter = 11 cm
cross-sectional area = 1.55 cm2
water flow rate = 2.46×10^−4 m3/s
to find out
How high will the water in the bucket rise
solution
we know that here
potential energy = kinetic energy
mgh = 1/2 mv²
multiply both sides by the 2 and we get
2mgh=mv²
solve it we get
√(2gh) = v ....................1
h = v²/2g ...............2
and
flow rate = A V
2.46×10^−4 = V 1.55×10^−4
V = 1.5870 m/s
so from 2
h = v²/2g
h = 1.5870²/ 2(9.81)
h = 0.1283 m
so height is 0.1283 m
