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-Dominant- [34]
4 years ago
8

NEED HELP ASAP PLEASE!!

Physics
1 answer:
Thepotemich [5.8K]4 years ago
5 0

1 g requires 80 cal of heat, then 100 g requires 80*100=8000 cal

1 cal = 4.1868 J

Then Q = 1910.767 J

<em>for you:</em>

The <u>heat energy</u> is defined from the equation:

Q=mCΔT

<em>where</em>

  • Q: the heat energy in (Joules).
  • m: the mass of the material which is heated in (kg).
  • C: the specific heat capacity in (J/kg.K).
  • ΔT: the change in the temperature in (K)
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24 POINTS!!!!!!!!!!!!
Karo-lina-s [1.5K]

Answer: Option (c) is the correct answer.

Explanation:

When the child is tossed up into the air then she gains kinetic energy as the child has moved from its initial position.

It is given that mass is 20 kg, velocity is 5 m/s^{2}, and height is 2 m.

Calculate the kinetic energy of child as follows.

             kinetic energy = \frac{1}{2}mv^{2}

                                      = \frac{1}{2}20 kg \times (5 m/s)^{2}

                                      = 10 kg \times 25 m^{2}/s^{2}

                                      = 250 kg m^{2}/s^{2}

Also, when child falls off the ground then she will have gravitational potential energy.

Calculate gravitational potential energy of child as follows.

            Potential energy = m × g × h

                                         = 20 kg \times 9.8 m/s^{2} \times 2 m

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3 0
3 years ago
Read 2 more answers
Which element has the least protons in the nucleus?
Arisa [49]

hydrogen

Explanation:

tbh Idk I'm just guessing

5 0
3 years ago
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A rocket, initially at rest, is fired vertically with an upward acceleration of 10 m/s2. At an altitude of 0.50 km, the engine o
noname [10]

Answer:

The maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km

Explanation:

Using the equations of motion,

When the rocket is fired from the ground,

u = initial velocity = 0 m/s (since it was initially at rest)

a = 10 m/s²

The engine cuts off at y = 0.5 km = 500 m

The velocity at that point = v

v² = u² + 2ay

v² = 0² + 2(10)(500) = 10000

v = 100 m/s

The velocity at this point is the initial velocity for the next phase of the motion

u = 100 m/s

v = final velocity = 0 m/s (at maximum height, velocity = 0)

y = vertical distance travelled after the engine shuts off beyond 0.5 km = ?

g = acceleration due to gravity = - 9.8 m/s²

v² = u² + 2gy

0 = 100² + 2(-9.8)(y)

- 19.6 y = - 10000

y = 510.2 m = 0.510 km

So, the maximum altitude reached with respect to the ground = 0.5 + 0.510 = 1.01 km

Hope this helps!!!

5 0
3 years ago
1. A block with a mass of 5.0 kg is pushed on a frictionless surface by applying a horizontal force of 80.0 N. The block starts
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Answer:

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2 years ago
Suppose a 4,000-kg elephant is hoisted 20 m above Earth’s surface. Use a calculator and follow the steps below to find the eleph
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GPE = 78,380 J
w = 39,240 N

First list what you know. You know the elephants mass and it’s height. You also know gravity on Earth. I will use g = 9.81.
m = 4,000 kg
h = 20 m
g = 9.81 m/s^2

You need to find the elephants weight. Weight = mass x gravity
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w = (4000 kg)(9.81 m/s^2)
w = 39,240 N (N = newtons)

Now, knowing the elephants weight, you can calculate its GPE.
Gravitational Potential Energy = weight x height

GPE = wh
GPE = (39,240N)(20m)
GPE = 78,380 J (J = joules)
4 0
3 years ago
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