Answer:
ok if I did this right the answer should be 675. sorry if it's wrong. I hope it's right.
The charge of the electrons is
.
The given parameters:
- <em>Number of revolution of the electron, N = 1.4 x 10⁶ rev per sec</em>
- <em>Flux density, B = 10⁻⁵ T</em>
- <em>Mass of electron, m = 9.11 x 10⁻³¹ kg</em>
<em />
The angular speed of the electron is calculated as follows;
![\omega = 2\pi N\\\\\omega = 2\pi \ \frac{rad}{1 \ rev} \times 1.4 \times 10^6 \ rev/s\\\\\omega = 8.798 \times 10^6 \ rad/s](https://tex.z-dn.net/?f=%5Comega%20%3D%202%5Cpi%20N%5C%5C%5C%5C%5Comega%20%3D%202%5Cpi%20%5C%20%5Cfrac%7Brad%7D%7B1%20%5C%20rev%7D%20%5Ctimes%201.4%20%5Ctimes%2010%5E6%20%5C%20rev%2Fs%5C%5C%5C%5C%5Comega%20%3D%208.798%20%5Ctimes%2010%5E6%20%5C%20rad%2Fs)
The charge of the electrons is calculated as follows;
![F_c= m\omega ^2 r\\\\F_{B}= qvB = q\omega r B \\\\F_c = F_B\\\\m\omega ^2 r = q\omega r B \\\\q = \frac{m\omega ^2 r}{\omega r B} \\\\q = \frac{m \omega }{B} \\\\q = \frac{9.11 \times 10^{-31} \times 8.798 \times 10^6}{10^{-5}} \\\\q = 8.02 \times 10^{-19} \ C](https://tex.z-dn.net/?f=F_c%3D%20m%5Comega%20%5E2%20r%5C%5C%5C%5CF_%7BB%7D%3D%20qvB%20%3D%20q%5Comega%20r%20B%20%5C%5C%5C%5CF_c%20%3D%20F_B%5C%5C%5C%5Cm%5Comega%20%5E2%20r%20%3D%20%20q%5Comega%20r%20B%20%5C%5C%5C%5Cq%20%3D%20%5Cfrac%7Bm%5Comega%20%5E2%20r%7D%7B%5Comega%20r%20B%7D%20%5C%5C%5C%5Cq%20%3D%20%5Cfrac%7Bm%20%5Comega%20%7D%7BB%7D%20%5C%5C%5C%5Cq%20%3D%20%5Cfrac%7B9.11%20%5Ctimes%2010%5E%7B-31%7D%20%5Ctimes%208.798%20%5Ctimes%2010%5E6%7D%7B10%5E%7B-5%7D%7D%20%5C%5C%5C%5Cq%20%3D%208.02%20%5Ctimes%2010%5E%7B-19%7D%20%5C%20C)
The charge of the electrons is
.
The complete question here:
Electrons execute 1.4*10^6 revolutions per sec in a magnetic field of flux density 10⁻⁵ T. What will be the value of charge of the electron?
Learn more about magnetic force of electrons here: brainly.com/question/3990732
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