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Brrunno [24]
4 years ago
7

The functional groups in an organic compound can frequently be deduced from its infrared absorption spectrum. A compound contain

ing C, H, and O exhibits strong, broad absorption band at 3430 cm-1, a sharp band at 3300, and a band at 2200 cm-1 (m). Relative absorption intensity: (s)=strong, (m)=medium, (w)=weak. What functional class(es) does the compound belong to? List only classes for which evidence is given here. Attach no significance to evidence not cited explicitly. Do not over-interpret exact absorption band positions. None of your inferences should depend on small differences like 10 to 20 cm-1. The functional class(es) of this compound is(are) .(Enter letters from the table below, in any order, with no spaces or commas.) a. alkane (List only if no other functional class applies.) b. alkene h. amine c. terminal alkyne i. aldehyde or ketone d. internal alkyne j. carboxylic acid e. arene k. ester f. alcohol l. nitrile g. ether
Chemistry
1 answer:
Klio2033 [76]4 years ago
7 0

The peaks at 3300 cm-1 and 2200 cm-1 are due to terminal alkyne group (triple bond between two carbons) and triple bonded C-H stretching

So

The answer is : terminal alkyne

Another peak near 3430 cm-1 must be due to an -OH group

so the answer is : alcohol

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Please Help
rewona [7]

Answer:

The correct answer is - they can create genetic diversity as well and reproduce without mate when necessary.

Explanation:

Sexual reproduction provides an organism with genetic diversity and variation by the process and it required two mates and a longer time to pollination and fertilization and is used in normal conditions.

In case of a threat, such organisms use asexual reproduction to increase their number as in asexual reproduction no need of mate, an organism can grow and increase on its own it provides to not to exitinct.

7 0
3 years ago
A 2.912 g sample of a compounds containing only C, H, and O was completely oxidized in a reaction that yielded 3.123 g of water
Taya2010 [7]

Answer:

Explanation:

18 gram of water contains 2 g of hydrogen

3.123 gram of water will contain 2 x 3.123 / 18 = .347 g of hydrogen .

44 gram of carbon dioxide contains 12 g of carbon

7.691 gram of carbon dioxide will contain 12 x 7.691 / 44 = 2.1 g of carbon .

So the sample will contain 2.912 - ( .347 + 2.1 ) g of oxygen .

= .465 g of oxygen .

moles of Carbon = 2.1 / 12 = .175

moles of hydrogen = .347 / 1 = .347

moles of oxygen = .465 / 16 = .029

Ratio of moles of carbon , oxygen and hydrogen ( C,O,H )

= 0.175 : 0.029 : 0.347

= .175/ .029 : 1 : .347 / .029

= 6 : 1 : 12

So empirical formula = C₆H₁₂O

Let the molecular formula be (C_6H_{12}O)_n

molecular weight = n ( 6 x 12 + 12x 1 + 16)

= 100 n

Given 100 n = 100.1

n = 1

Molecular formula = C₆H₁₂O.

3 0
3 years ago
(03.03 LC)
scoundrel [369]
I believe the answer is option B. The bonded pair of valence electrons are shown using circles
8 0
3 years ago
What is different about atoms after a redox reaction has happened?
klasskru [66]
The difference is the amount of oxygen in the compound
3 0
3 years ago
Lab Report
Diano4ka-milaya [45]

Answer:

The purpose of the experiment is to see how water of different temperature and salinity affect the density.

Explanation:

Temperature and salinity directly affect the density of the water. Water of low temperature is more dense than water of high temperature, BUT, (fresh)water with no salt is less dense than (sea)water with more salt, so temperature and salinity change density of water.

3 0
2 years ago
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