Unsaturation (IHD) 2 hydrogen Needed
IHD = [(2n+2) -H]/2
(H: X=1, N=-1, O= zero)
Unsaturation:
Double bonds = 1
Rings = 1
Triple Bonds = 2
The degrees of unsaturation in a molecule are additive — a
molecule with one double bond has one degree of unsaturation, a molecule with
two double bonds has two degrees of unsaturation, and so forth.
Answer:


Explanation:
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In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

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Explanation:
Water is a polar solvent as the hydrogen and oxygen atom has large difference in their electronegativities.
Oxygen atom is highly electronegative as compared to hydrogen atom therefore, it pulls the electrons of hydrogen atom closer towards itself.
As a result, two poles will create forming a partial positive charge on the hydrogen atom and partial negative charge on the oxygen atom.
Thus, we can conclude that high electronegativity difference between oxygen and hydrogen is the cause of polarity in water molecules.
Answer:
The number of
atoms in the unit cell is 2
Explanation: