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Allisa [31]
4 years ago
5

A painter leans a 20-ft ladder against a building. The base of the ladder is 12 ft from the building. To the nearest foot, how h

igh on the building does the ladder reach?
Mathematics
2 answers:
denpristay [2]4 years ago
6 0
The ladder would reach 16 feet on the building.
Pythagorean theorem helps find this answer. a^2 +b^2 = c^2
marshall27 [118]4 years ago
5 0

using Pythagorean Theorem

 you have 20^2 = 12^2 +X^2

400 = 144 +x^2

256 =x^2

x = sqrt(256)

x = 16

 the ladder reaches 16 feet up the building

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The two quadrilaterals below are similar. What is the length of EF?
damaskus [11]

EF = 15 cm.

Step-by-step explanation:

Step 1:

If the quadrilaterals, ABCD and EFGH are similar their side lengths will be of the same ratio throughout.

Comparing the quadrilaterals, we have AB and EF are similar, BC and FG are similar, CD and GH are similar, DA and HE are similar.

So the ratio of all these sides will be equal.

Step 2:

\frac{AB}{EF} :\frac{BC}{FG} : \frac{CD}{GH} :\frac{DA}{HE} .

Of these lengths, we only have the values for AB, BC, CD, DA, GH, HE and need to determine the length of EF. By substituting the known values the ratio becomes;

\frac{5}{EF} :\frac{4}{12} :\frac{6}{18} .

\frac{5}{EF} : \frac{1}{3} : \frac{1}{3} .

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6 0
3 years ago
Need help with this problem
alexandr1967 [171]

Answer:

x = 10

Step-by-step explanation:

Since the triangles are similar the ratios of corresponding sides are equal

\frac{20}{20+8} = \frac{3x}{4x+2}, that is

\frac{20}{28} = \frac{3x}{4x+2} ( cross- multiply )

20(4x + 2) = 84x

80x + 40 = 84x ( subtract 80x from both sides )

40 = 4x ( divide both sides by 4 )

x = 10



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3 years ago
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belka [17]
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50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt
7 0
3 years ago
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