+4 next terms are 33,37,41,44,47,50 and so on.....
EF = 15 cm.
Step-by-step explanation:
Step 1:
If the quadrilaterals, ABCD and EFGH are similar their side lengths will be of the same ratio throughout.
Comparing the quadrilaterals, we have AB and EF are similar, BC and FG are similar, CD and GH are similar, DA and HE are similar.
So the ratio of all these sides will be equal.
Step 2:

Of these lengths, we only have the values for AB, BC, CD, DA, GH, HE and need to determine the length of EF. By substituting the known values the ratio becomes;


So
cm. Which is the second option.
Answer:
x = 10
Step-by-step explanation:
Since the triangles are similar the ratios of corresponding sides are equal
=
, that is
=
( cross- multiply )
20(4x + 2) = 84x
80x + 40 = 84x ( subtract 80x from both sides )
40 = 4x ( divide both sides by 4 )
x = 10
The speed of the ball is
ds/dt = 32t
At t =1/2 s
ds/dt = 16 ft/s
The distance from the ground
50 - 16(1/2)^2 = 46 ft
The triangles formed are similar
50/46 = (30 + x)/x
x = 345 ft
50 / (50 - s) = (30 + x)/x
Taking the derivative and substituing
ds/dt = 16
and
Solve for dx/dt