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2 years ago

A flower bed is in the shape of a triangle with a base of 15 feet and a hight of 9 feet what is the area of the flower bed

Mathematics

2 answers:

Solnce55 [7]2 years ago

5 0

Answer:

area of a triangle is 1/2bh

1/2 X 15 x 9 = 67.5 square feet

Step-by-step explanation:

sesenic [268]2 years ago

5 0

For this case we must find the area of a flower bed with a triangle shape.

The area of a triangle is given by:

$A = \frac {b * h} {2}$

Where:

b: It's the base

h: It's the height

Substituting the given values:

$A = \frac {15 * 9} {2}\\A = 67.5\ ft ^ 2$

Answer:

$A = 67.5\ ft ^ 2$

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Convert the Cartesian equation (x 2 + y 2)2 = 4(x 2 - y 2) to a polar equation.

SashulF [63]

ANSWER

${r}^{2} = 4 \cos2\theta$

EXPLANATION

The Cartesian equation is

${( {x}^{2} + {y}^{2} )}^{2} = 4( {x}^{2} - {y}^{2} )$

We substitute

$x = r \cos( \theta)$

$y = r \sin( \theta)$

and

${x}^{2} + {y}^{2} = {r}^{2}$

This implies that

${( {r}^{2} )}^{2} = 4(( { r \cos\theta) }^{2} - {(r \sin\theta) }^{2} )$

Let us evaluate the exponents to get:

${r}^{4} = 4({ {r}^{2} \cos^{2}\theta } - {r}^{2} \sin^{2}\theta)$

Factor the RHS to get:

${r}^{4} = 4{r}^{2} ({ \cos^{2}\theta } - \sin^{2}\theta)$

Divide through by r²

${r}^{2} = 4 ({ \cos^{2}\theta } - \sin^{2}\theta)$

Apply the double angle identity

$\cos^{2}\theta -\sin^{2}\theta= \cos(2 \theta)$

The polar equation then becomes:

${r}^{2} = 4 \cos2\theta$

7 0

3 years ago

What are m∠1 and m∠2?

tankabanditka [31]

Answer:

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2 years ago

1/2 + (-1/4)=????????????

erica [24]

Answer:

$\frac{1}{4}$

Step-by-step explanation:

$\frac{1}{2}$ = $\frac{2}{4}$ We need a common denominator before we can add.

$\frac{2}{4}$ + $\frac{-1}{4}$ means the same thing as

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1 year ago

If a/2b =3/5 and 4b/3c=1/7, then a/c= I will mark you brainlist whoever get this correct

ioda

Answer:

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2 years ago

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Kaylis [27]

Answer:

Step-by-step explanation:

h + k

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6+14

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3 years ago