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4 years ago

9

For each curve Below, find the values of x for which the curve is increasing

1 answer:

Vikki [24]4 years ago

4 0

I ——x=2
ii——x=1
iii——x=2

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when the wimen sells 90 oranges Rs160 with dicount of 20%,how many oranges she sell by Rs112 with profit of 20%

Fynjy0 [20]

She sold 42 oranges with profit 20%

Step-by-step explanation:

The woman sells 90 oranges by RS.160

This price with discount of 20%

We need to find how many oranges she sell by Rs.112 with profit of 20%

Selling price = cost price - discount ⇒ discount case
Selling price = cost price + profit ⇒ profit case

Assume that cost price of an orange is x

∵ She sells 90 oranges with Rs.160

- Find the selling price of 1 orange by dividing 160 by 90

∴ The selling price of an orange = $\frac{160}{90}=\frac{16}{9}$

∵ She sold them with discount 20%

∵ The cost price of an orange is x

- Find the 20% of x

∵ Discount = 20% × x = $\frac{20}{100}$ × x = 0.2x

- To find the selling price subtract 0.2x from x

∴ The selling price = x - 0.2x

∴ The selling price of an orange = 0.8x

- Equate 0.8x by $\frac{16}{9}$ to find x

∵ 0.8x = $\frac{16}{9}$

- Divide both sides by 0.8

∴ x = $\frac{20}{9}$

Assume that the number of oranges is y

∵ She sell y oranges for Rs.112 with profit 20%

∵ The cost price of an orange is $\frac{20}{9}$

- Find 20% of $\frac{20}{9}$

∵ Profit = 20% × $\frac{20}{9}$ = $\frac{20}{100}.\frac{20}{9}=\frac{4}{9}$

- Add $\frac{4}{9}$ to cost price to find the selling price

∴ The selling price of an orange = $\frac{20}{9}$ + $\frac{4}{9}$

∴ The selling price of an orange = $\frac{24}{9}$

- To find y divide 112 by selling price of an orange

∵ y = 112 ÷ $\frac{24}{9}$

∴ y = 42

She sold 42 oranges with profit 20%

Learn more:

You can learn more about percentage in brainly.com/question/12284722

#LearnwithBrainly

4 0

3 years ago

rebecca wants to crochet a scarf that is at least 4.4 feet long. So far, she's completed 2.5 feet. How much more does Rebecca in

vlabodo [156]

Answer:

4.4 < 2.5 +x

She needs to crochet at least 1.9 more ft

Step-by-step explanation:

She wants the scarf to be at least 4.4 ft long

4.4< scarf

The scarf is 2.5 ft long now

She will crochet x more ft

4.4 < 2.5 +x

Subtract 2.5 from each side

4.4 -2.5 < 2.5+x-2.5

1.9 <x

She needs to crochet at least 1.9 more ft

3 0

3 years ago

Which of the following can cause market failure?

nalin [4]

Answer: C

Step-by-step explanation: not enough information

5 0

3 years ago

What is the slope intercept form of the equation y+5= 4(x+8)

hram777 [196]

Answer:

$y=4x+27$

Step-by-step explanation:

we know that

The equation of the line into slope intercept form is equal to

$y=mx+b$

where

m is the slope

b is the y-intercept

we have

$y+5=4(x+8)$ ----> equation of the line into point slope form

Convert to slope intercept form

Isolate the variable y

Distributed left side

$y+5=4x+32$

subtract 5 both sides

$y=4x+32-5\\ y=4x+27$

7 0

3 years ago

The point P(7, −2) lies on the curve y = 2/(6 − x). (a) If Q is the point (x, 2/(6 − x)), use your calculator to find the slope

NARA [144]

Answer:

a) (i) $m = 2.22$ , (ii) $m = 2$ , (iii) $m = 2$ , (iv) $m = 2$ , (v) $m = 1.82$ , (vi) $m = 2$ , (vii) $m = 2$ , (viii) $m = 2$ ; b) $m \approx 2$ ; c) The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

Step-by-step explanation:

a) The slope of the secant line PQ is represented by the following definition of slope:

$m = \frac{\Delta y}{\Delta x} = \frac{y_{Q}-y_{P}}{x_{Q}-x_{P}}$

(i) $x_{Q} = 6.9$ :

$y_{Q} =\frac{2}{6-6.9}$

$y_{Q} = -2.222$

$m = \frac{-2.222 + 2}{6.9-7}$

$m = 2.22$

(ii) $x_{Q} = 6.99$

$y_{Q} =\frac{2}{6-6.99}$

$y_{Q} = -2.020$

$m = \frac{-2.020 + 2}{6.99-7}$

$m = 2$

(iii) $x_{Q} = 6.999$

$y_{Q} =\frac{2}{6-6.999}$

$y_{Q} = -2.002$

$m = \frac{-2.002 + 2}{6.999-7}$

$m = 2$

(iv) $x_{Q} = 6.9999$

$y_{Q} =\frac{2}{6-6.9999}$

$y_{Q} = -2.0002$

$m = \frac{-2.0002 + 2}{6.9999-7}$

$m = 2$

(v) $x_{Q} = 7.1$

$y_{Q} =\frac{2}{6-7.1}$

$y_{Q} = -1.818$

$m = \frac{-1.818 + 2}{7.1-7}$

$m = 1.82$

(vi) $x_{Q} = 7.01$

$y_{Q} =\frac{2}{6-7.01}$

$y_{Q} = -1.980$

$m = \frac{-1.980 + 2}{7.01-7}$

$m = 2$

(vii) $x_{Q} = 7.001$

$y_{Q} =\frac{2}{6-7.001}$

$y_{Q} = -1.998$

$m = \frac{-1.998 + 2}{7.001-7}$

$m = 2$

(viii) $x_{Q} = 7.0001$

$y_{Q} =\frac{2}{6-7.0001}$

$y_{Q} = -1.9998$

$m = \frac{-1.9998 + 2}{7.0001-7}$

$m = 2$

b) The slope at P (7,-2) can be estimated by using the following average:

$m \approx \frac{f(6.9999)+f(7.0001)}{2}$

$m \approx \frac{2+2}{2}$

$m \approx 2$

The slope of the tangent line to the curve at P(7, -2) is 2.

c) The equation of the tangent line is a first-order polynomial with the following characteristics:

$y = m\cdot x + b$

Where:

$x$ - Independent variable.

$y$ - Depedent variable.

$m$ - Slope.

$b$ - x-Intercept.

The slope was found in point (b) (m = 2). Besides, the point of tangency (7,-2) is known and value of x-Intercept can be obtained after clearing the respective variable:

$-2 = 2 \cdot 7 + b$

$b = -2 + 14$

$b = 12$

The equation of the tangent line to curve at P (7, -2) is $y = 2\cdot x + 12$ .

7 0

3 years ago