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3 years ago

Simplify (3x^-2y^4)^-3

Mathematics

1 answer:

Anuta_ua [19.1K]3 years ago

5 0

Answer:

x^6/27y^12

Step-by-step explanation:

(3. 1?x^2 y^4)^3

(3y^4/x^2)^3

witch you get x^6/27y^12

hope i helped

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Evaluate the expression 1/4[x(2y+3z)] x=8 y=3z=5/3

ladessa [460]

Answer:

Step-by-step explanation:

x = 8 ; y = 5/3

$3z = \dfrac{5}{3}$

$\dfrac{1}{4}[x(2y+3z)] =\dfrac{1}{4}[8*(2*\dfrac{5}{3}+\dfrac{5}{3})]\\\\=\dfrac{1}{4}(8*(\dfrac{10}{3}+\dfrac{5}{3})]\\\\=\dfrac{1}{4}(8*\dfrac{15}{3})\\\\=\dfrac{1}{4}*8*5\\\\=2*5\\\\=10$

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2 years ago

If DM=35, what is the value of r ?

balu736 [363]

Answer:

r=12.5 units

Step-by-step explanation:

Well assuming that DM means diameter of a circle, then r should be the radius of the circle.

Diameter of a circle is twice the radius of the circle, hence with the value of Diameter, you should half it to get the value of radius.

Given diameter =25

Radius will be= 25/2 = 12.5 units

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2 years ago

4. In Ghana the high temperatures in degrees Fahrenheit for five days in January were -14°

S_A_V [24]

Answer:

Step-by-step explanation:

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2 years ago

Given: is an angle bisector of ∠JMK<br><br><br>Prove: m

astraxan [27]

Answer:

An angle bisector is a line passing through the vertex of the angle that cuts the angle into two equal smaller angles.

Given: MN is angle bisector,

then

$\angle JMN \cong \angle NMK$ ....... [1]

Congruent angles are two or more angles that have the same measure.

then;

by definition of congruent angles

[1]⇒ $m\angle JMN = m\angle NMK$ ......[2]

By the Angle addition postulates states that if M is in the interior of ∠JMK then,

$m\angle JMN+m\angle NMK =m\angle JMK$ ......[3]

Now, by substitution property ; substitute the equation [2] in [3] we get;

$m\angle JMN+m\angle JMN =m\angle JMK$ ......[4]

Like terms terms whose variables are the same

Combine like terms in equation [4] we get

$2 \cdot m\angle JMN=m\angle JMK$ ......[5]

Division property of equality states that you divide the same number to both sides of an equation.

Divide by 2 to both sides in equation [5] , we get

$m\angle JMN= \frac{1}{2} m\angle JMK$

5 0

3 years ago

How do I solve this out??

GuDViN [60]

<h3>Answer:</h3>

(x, y) = (7, -5)

<h3>Step-by-step explanation:</h3>

It generally works well to follow directions.

The matrix of coefficients is ...

$\left[\begin{array}{cc}2&4\\-5&3\end{array}\right]$

Its inverse is the transpose of the cofactor matrix, divided by the determinant. That is ...

$\dfrac{1}{26}\left[\begin{array}{ccc}3&-4\\5&2\end{array}\right]$

So the solution is the product of this and the vector of constants [-6, -50]. That product is ...

... x = (3·(-6) +(-4)(-50))/26 = 7

... y = (5·(-6) +2·(-50))/26 = -5

The solution using inverse matrices is ...

... (x, y) = (7, -5)

7 0

2 years ago