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3 years ago

A population of insects increases by 2.5% per year.

Mathematics

1 answer:

maria [59]3 years ago

3 0

Answer:

The answer is 0.21% increase monthly.

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Explain why the force exerted by the muscle is much greater than the weight of the phone<br>

lord [1]

Answer:

sorry i dont understand it

Step-by-step explanation:

8 0

3 years ago

HELP ASAP!!!!! Given: Point B is on the perpendicular bisector of AC¯¯¯¯¯. BD¯¯¯¯¯ bisects AC¯¯¯¯¯ at point D. Prove: B is equid

Harlamova29_29 [7]

Answer: Missing parts are,

In first blank, $AD\cong DC$ ,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

$\angle BDA\cong \angle BDC$ ( right angles )

$BD\cong BD$ ( reflexive)

Thus, By SAS ( side angle side )postulate,

$\triangle ADB\cong \triangle CDB$

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

$AB\cong CB$

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.

7 0

3 years ago

Read 2 more answers

Find the greatest common factor of 15 x²y³ and -18 x³yz .

Masteriza [31]

Answer:

3 x² y¹

Step-by-step explanation:

15 x²y³ = 3. 5. x². y³

-18x³yz = -2. 3². x³. y¹. z¹

so, the GCF = 3. x². y¹

7 0

3 years ago

Read 2 more answers

45 Points! Please explain your answer! Brainliest to whoever does the best!

Alex73 [517]

Answer:

$\sf \boxed{\sf \frac{3}{2} } \ miles \ per \ day$

Explanation:

$\sf unit \ rate: \dfrac{Total \ distance \ (miles)}{Total \ time \ taken \ (day)}$

Here given:

$Total \ Distance : 8\dfrac{1}{4} \ or \ 8.25$

$Total \ Time \ taken : 5\dfrac{1}{2} \ or \ 5.5$

Find unit rate:

$\rightarrow \sf unit \ rate: \dfrac{8.25 }{5.5 }$

$\rightarrow \sf unit \ rate: 1.5 \ miles \ per \ day$

7 0

2 years ago

A mirror frame in the shape of an oval is shown below. The ends of the frame form semicircles: An oval is formed by a rectangle

sesenic [268]

We can solve this by first finding the diameter of the two semicircles. We know that the width of the rectangle is 27 inches, which also happens to be the diameter of the circle.

The circumference of a circle is 2πr or πd. The problem says that it is a semicircle, however, it says that there are two of them. Since the two semicircles are the same size, we know that they can combine to form one circle, so we can just find the circumference of one circle to account for both of the semicircles:

C=27π inches

We also know that the length of the rectangle is 60 inches. We only want to find the perimeter of the frame, so we don't have to account for the widths of the rectangle because it is inside the frame. Therefore, the two sides of the rectangle together are 120 inches. Now we can add this to the circumference we found:

120+27π inches or 204.78 inches (depends on what your teacher is asking for)

5 0

3 years ago

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