The melting point of camphor is 178.4°C which is also the freezing point.
After the unknown substance is added, the freezing point is reduced to 173.6°C.
The freezing point depression is
178.4°C - 173.6°C = 4.8°C
The molar mass of the substance can be found using the equation
Kf m = 4.8
37.7 (0.664 / MW) = 4.8
MW = 5.22 g/mol
Answer: 14.3%Explanation: In order to find the mass percent of hydrogen in this compound, you must determine how many grams of hydrogen you'd get in 100 g of compound.
In your case, you know that an unknown mass of hydrogen reacts with 0.771 g of carbon to form 0.90 g of hydrocarbon, which is a compound that contains only carbon and hydrogen.
Use the total mass of the hydrocarbon to determine how many grams of hydrogen reacted with the carbon.
Now, if 0.90 g of this compound contain 0.129 g of hydrogen, it follows that 100 g of this compound will contain.
So, if 100 g of this compound contain 14.33 g of hydrogen, it follows that the mass percent of hydrogen is 14.3%
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<span>the water is the solvent, and the powder is the solute. This is also a solution altogether. </span>
A melting point of a substance is a point at which the sample or substance start converting in liquid. For most substances, melting and freezing points are approximately equal. For example, the melting point and freezing point of mercury is 234.32 kelvins (−38.83 °C or −37.89 °F). Hope this helped!! :)
Answer:
Follows are the solution to the given question:
Explanation:
Dry Soil weight = solid soil weight = 
solid soil volume =
saturated mass soil = 
The weight of the soil after drainage is =
Water weight for soil saturation = 
Water volume required for soil saturation =
Sample volume of water: 
Soil water retained volume = (draining field weight - dry soil weight)
(Its saturated water volume is equal to the volume of voids)
