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Jlenok [28]
3 years ago
6

How to write steam in chemical equations

Chemistry
1 answer:
GalinKa [24]3 years ago
7 0

Answer:

How to write steam in chemical equations???

Chemical equations are symbolic descriptions of chemical reactions wherein the reactants and the products are represented in terms of their respective chemical equations. They often include the use of symbols to represent variables including the path of the reaction and the physical responses of the reacting entities.

The equation in which the number of atoms of all the molecules is equal on both sides of the equation is known as a balanced chemical equation.

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Is a diamond a homogeneous or heterogeneous mixture or a substance
DerKrebs [107]

Answer:

heterogeneous

Explanation:

It's a heterogeneous mixture. Diamond is made of just one element: carbon. Each carbon atom in diamond is connected to four other carbon atoms, in a crystal that extends on and on. There are other forms of pure carbon where the atoms are bonded differently, notably charcoal and graphite.

5 0
3 years ago
List 2 ways strong and weak acids differ.
Soloha48 [4]
A strong acid is an acid that ionizes completely in an aqueous solution. A strong acid will always loose a proton (A H+) when dissolved in H2O. In other words, a strong acid is always on its toes and quite efficient in giving off protons. A weak acid is one that ionizes partially in a solution.There you go, I hope this helped.
8 0
3 years ago
Divide rs 120 I three parts which are in THE ratio of 1:2:3.​
soldier1979 [14.2K]

Answer:

20,40,60

Explanation:

Let the three parts be 1x, 2x and 3x

The the sum of three parts will be 1x+2x+3x = 120

6x=120

x=120/6

x=20

1x= 20x1=20

2x= 20x2=40

3x= 20x3=60

So 120 is divided in three parts that is 20,40,60

Answer From Gauth Math

8 0
3 years ago
AgCl is..<br> A)an element <br> B)a compound <br> C.)a mixture
SOVA2 [1]
It is an A compound
6 0
3 years ago
Read 2 more answers
The reaction between nitrogen dioxide and carbon monoxide is NO2(g)+CO(g)→NO(g)+CO2(g)NO2(g)+CO(g)→NO(g)+CO2(g) The rate constan
galina1969 [7]

Answer:

k_2=2.55\ {Ms}^{-1}

Explanation:

Using the expression,

\ln \dfrac{k_{1}}{k_{2}} =-\dfrac{E_{a}}{R} \left (\dfrac{1}{T_1}-\dfrac{1}{T_2} \right )

Where,

k_1\ is\ the\ rate\ constant\ at\ T_1

k_2\ is\ the\ rate\ constant\ at\ T_2

E_a is the activation energy

R is Gas constant having value = 8.314 J / K mol  

k_2=?

k_1=2.57\ {Ms}^{-1}

T_1=701\ K  

T_2=525\ K  

E_a=1.5\times 10^2\ kJ/mol

So,  

\ln \:\frac{2.57}{k_2}\:=-\frac{1.5\times \:10^2}{8.314}\times \left(\frac{1}{701}-\frac{1}{525}\right)\:\:

k_2=\frac{2.57}{e^{\frac{352}{40796.798}}}=2.55\ {Ms}^{-1}

7 0
3 years ago
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