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german
3 years ago
13

A 20-volt relay has a coil resistance of 200 ohms. How much current does it draw? (I=0.1A)

Physics
1 answer:
TEA [102]3 years ago
8 0

Answer:

Explanation:

a) According to ohm's law

V = IR

V is the supply voltage

R is the resistance

I is the current

Given Resistance = 200ohms

Voltage = 20V

I = V/R

I = 20/200

I = 0.1Amperes

b) Using the ohm's law formula

V= IR

Where voltage = 12volts

Current I = 3A

Resistance R = V/I

R = 12/3

R = 4ohms

c) Power generated by the battery is expressed as P = IV

I = P/V

Given Power = 2Watts

V = 1.5volts

I = 2/1.5

I = 1.33A

d) similarly, power = current I × voltage V

V = P/I

Given P = 90watts

I = 4.5A

V = 90/4.5

V = 20volts

e) Given power = 1.5kW = 1500watts

Voltage = 300volts

I = P/V

I = 1500/300

I = 5A

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