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aleksklad [387]
3 years ago
6

Coherent light with wavelength 460 nm falls on a pair of slits. On a screen 1.86 m away, the distance between dark fringes is 3.

90 mm. What is the slit separation?
Physics
1 answer:
Jobisdone [24]3 years ago
7 0

Answer:

The split separation d = 2.12 * 10^-4 m

Explanation:

Mathematically, for a double split interference, the relation between separation of slit and fringe width is given by the formula;

d = Rλ/Δy

Where R represents the distance of screen from the slit given as 1.86m , λ is the wavelength of incident light given as 460 nm ,

Δy is the fringe width given as 3.90 nm

plugging these values into the equation, we have;

d = (1.86)(460 * 10^-9)/(3.9 * 10^-3)

d = 2.12 * 10^-4 m

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kolezko [41]
80 km per hour i believe. i’ll admit i’m american so we don’t use km lol, but the math should be the same. total distance = 120km, and total time = 1.5 hours. 120/1.5 = 80.
3 0
3 years ago
Students in an introductory physics lab are producing a region of uniform electric field by applying a voltage to two 20-cm-diam
earnstyle [38]

Answer:

69000 V

Explanation:

E = Electric field = 3\times 10^6\ V/m

d = Distance between plates = 2.3 cm

When we multiply the electric field strength and the distance between the plates of a capacitor we get the maximum voltage.

Maximum voltage is given by

V_m=Ed\\\Rightarrow V_m=3\times 10^6\times 2.3\times 10^{-2}\\\Rightarrow V_m=69000\ V

The highest voltage the students can use is 69000 V

4 0
4 years ago
A metal block of mass 3 kg is falling downward and has velocity of 0.44 m/s when it is 0.8 m above the floor. It strikes the top
Anton [14]

Answer:

y_{max} = 0.829\,m

Explanation:

Let assume that one end of the spring is attached to the ground. The speed of the metal block when hits the relaxed vertical spring is:

v = \sqrt{(0.8\,\frac{m}{s})^{2} + 2\cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.4\,m)}

v = 2.913\,\frac{m}{s}

The maximum compression of the spring is calculated by using the Principle of Energy Conservation:

(3\,kg)\cdot (9.807\,\frac{m}{s^{2}})\cdot (0.4\,m) + \frac{1}{2}\cdot (3\,kg)\cdot (2.913\,\frac{m}{s} )^{2} = (3\,kg) \cdot (9.807\,\frac{m}{s^{2}})\cdot (0.4\,m-\Delta s) + \frac{1}{2}\cdot (2000\,\frac{N}{m})\cdot (\Delta s) ^{2}

After some algebraic handling, a second-order polynomial is formed:

12.728\,J = \frac{1}{2}\cdot (2000\,\frac{N}{m} )\cdot (\Delta s)^{2} - (3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot \Delta s

1000\cdot (\Delta s)^{2}-29.421\cdot \Delta s - 12.728 = 0

The roots of the polynomial are, respectively:

\Delta s_{1} \approx 0.128\,m

\Delta s_{2} \approx -0.099\,m

The first root is the only solution that is physically reasonable. Then, the elongation of the spring is:

\Delta s \approx 0.128\,m

The maximum height that the block reaches after rebound is:

(3\,kg) \cdot (9.807\,\frac{m}{s^{2}} )\cdot (0.4\,m-\Delta s) + \frac{1}{2}\cdot (2000\,\frac{N}{m})\cdot (\Delta s)^{2} = (3\,kg)\cdot (9.807\,\frac{m}{s^{2}} )\cdot y_{max}

y_{max} = 0.829\,m

4 0
3 years ago
Read 2 more answers
What influences the path that surface currents take?
polet [3.4K]
For the answer to the question above asking <span>What influences the path that surface currents take?</span>
It's the force of the wind that influences the path of surface currents.
I hope my answer helped you. feel free to ask more questions. Have a nice day!
4 0
3 years ago
Read 2 more answers
A sound wave has a frequency of 510 Hz in air. Which of these is closest to the wavelength of this sound? (The speed of sound in
Dahasolnce [82]

Answer:

b) the length of car

Explanation:

This is because 520 divided by 343 m/s.) would equal the length of a car.

8 0
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