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Doss [256]
3 years ago
8

A path 1m wide is built along the border and inside a square garden of 30m. What’s the area of the path

Mathematics
1 answer:
tia_tia [17]3 years ago
6 0

Along two opposite sides of the square, the path is 30 m long and 1 m wide.

Along the other two opposite sides of the square, the path is 28 m long and 1 m wide.

area = 2(30 m * 1 m) + 2(28 m * 1 m) = 60 m^2 + 56 m^2 = 116 m^2

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Math - Use unit conversion factor to convert the units.
nlexa [21]

Answer: 240 minutes, 20 cups, 4000 pounds

<u>Step-by-step explanation:</u>

Use the following conversions:

1 hour = 60 minutes

2 cups = 1 pint

2 pints = 1 quart

1 ton = 2000 pounds

4\ hours\times \dfrac{60\ minutes}{1\ hour}=\large\boxed{240\ minutes}\\\\\\\\5\ quarts \times \dfrac{2\ pints}{1\ quart}\times \dfrac{2\ cups}{1\ pint}=\large\boxed{20\ cups}\\\\\\\\2\ tons\times \dfrac{2000\ pounds}{1\ ton}=\large\boxed{4000\ pounds}

8 0
3 years ago
Bob Nale is the owner of Nale’s Quick Fill. Bob would like to estimate the mean number of gallons of gasoline sold to his custom
ira [324]

Answer:

a) The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

b) The 99% confidence interval would be given by (4.969;6.431)    

c) We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

Step-by-step explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean for the sample  

\mu population mean (variable of interest)

\sigma=1.9 represent the population standard deviation

n=45 represent the sample size  

2) Part a

The best estimator for the population mean is given by the sample mean \hat \mu = \bar X = 5.70

3) Part b. Develop a 99 percent confidence interval for the population mean.

The confidence interval for the mean is given by the following formula:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

Since the Confidence is 0.95 or 95%, the value of \alpha=0.01 and \alpha/2 =0.005, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.005,0,1)".And we see that z_{\alpha/2}=2.58

Now we have everything in order to replace into formula (1):

5.7-2.58\frac{1.9}{\sqrt{45}}=4.969    

5.7+2.58\frac{1.9}{\sqrt{45}}=6.431

So on this case the 99% confidence interval would be given by (4.969;6.431)    

4) Part c. Interpret the meaning of part (b).

On this case we can say this: We are 99% confident that the true mean for th number of gallons of gasoline  sold to his customers is between 4.969 and 6.431.

4 0
3 years ago
After 1 year, $800 deposited in a savings account with simple interest had earned $64 in
stepan [7]

Answer:

8%

Step-by-step explanation:

We will use the equation provided to solve this problem.

I=Prt

Lets plug in the values:

64=800x(1)     First, divide both sides by 800.

.08=x(1)         Multiply x by 1

x = .08

Now, we multiply .08 by 100 to get our interest rate:

(.08)100 = 8

The interest rate is 8%

7 0
3 years ago
Solve for a side in right triangles
elena55 [62]

Answer:

4.50 = ?

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

sin theta = opposite / hypotenuse

sin 40 = ? / 7

Multiply each side by 7

7 sin 40 = ?

4.499513268 = ?

To the nearest hundredth

4.50 = ?

5 0
3 years ago
What is the end behavior? 10 points!!
Colt1911 [192]

Given:

The given function is:

f_1(x)=-3\cdot 2^{x-5}-4

The graph of the function is given.

To find:

The end behavior of the given function.

Solution:

We have,

f_1(x)=-3\cdot 2^{x-5}-4

From the given graph it is clear that the function approaches to -4 at x approaches negative infinite and the function approaches to negative infinite at x approaches infinite.

f_1(x)\to -4 as x\to -\infty

f_1(x)\to -\infty as x\to \infty

Therefore, the end behaviors of the given function are:

f_1(x)\to -4 as x\to -\infty

f_1(x)\to -\infty as x\to \infty

4 0
3 years ago
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