Question

If the specific heat of a metal is 0.850 J/g °C, what is its atomic weight?

Answer 1

As we know that with respect to oxygen atom taken as reference the product of atomic mass and specific heat of a metal will remain constant.

this product is equal to 0.38

so here we will say that let atomic mass of the metal is M

so with respect to oxygen atom its mass is given as

$m = \frac{M}{16}$

now we will have

$\frac{M}{16} \times 0.850 = 0.38$

now we will have

$M = 7$

so atomic mass of the metal is 7 g/mol

Answer 2

Answer:

Its atomic weight is 0.00753N

Explanation:

Dulong and Petit law states that atoms of all elements have the same heat capacity so their specific heat is inversely related to their respective atomic weights.

       i.e      $S_{H}$ $\alpha \frac{1}{A_{w} }$

where $S_{H}$ is the specific heat of the object and $A_{w}$ is the atomic weight of the object.

       ⇒ $S_{H}$ × $A_{w}$ = constant = 6.4

$S_{H}$ = 0.850J/g°C = 850 J/KgK

             $A_{w}$ = $\frac{6.4}{850}$

                   = 0.00753N