Answer:
Explanation:
change in flux = no of turns x area of loop x change in magnetic field
= 1 x π 65² x 10⁻⁶ x ( 650 - 350 ) x 10⁻³
= 3.9 x 10⁻³ weber .
rate of change of flux = change of flux / time
= 3.9 x 10⁻³ / .10
= 39 x 10⁻³ V
= 39 mV .
Since the magnetic flux is directed outside page and it is increasing , induced current will be clockwise so that magnetic field is produced in opposite direction to reduce it , as per Lenz's law.
First question: 800J
Second question: 20.4m
Answer:
Work out = 28.27 kJ/kg
Explanation:
For R-134a, from the saturated tables at 800 kPa, we get
= 171.82 kJ/kg
Therefore, at saturation pressure 140 kPa, saturation temperature is
= -18.77°C = 254.23 K
At saturation pressure 800 kPa, the saturation temperature is
= 31.31°C = 304.31 K
Now heat rejected will be same as enthalpy during vaporization since heat is rejected from saturated vapour state to saturated liquid state.
Thus,
=
= 171.82 kJ/kg
We know COP of heat pump
COP = 
= 
= 6.076
Therefore, Work out put, W = 
= 171.82 / 6.076
= 28.27 kJ/kg