The position at time t is
x(t) = 0.5t³ - 3t² + 3t + 2
When the velocity is zero, the derivative of x with respect to t is zero. That is,
x' = 1.5t² - 6t + 3 = 0
or
t² - 4t + 2 = 0
Solve with the quadratic formula.
t = (1/2) [ 4 +/- √(16 - 8)] = 3.4142 or 0.5858 s
When t =0.5858 s, the position is
x = 0.5(0.5858³) - 3(0.5858²) + 3(0.5858) + 2 = 2.828 m
When t=3.4142 s, the position is
x = 0.5(3.4142³) - 3(3.4142²) + 3(3.4142) + 2 = -2.828 m
Reject the negative answer.
Answer:
The velocity is zero when t = 0.586 s, and the distance is 2.83 m
When the acceleration is zero, the second derivative of x with respect to t is zero. That is,
3t - 6 = 0
t = 2
The distance traveled is
x = 0.5(2³) - 3(2²) + 3(2) + 2 = 0
Answer:
When the acceleration is zero, t = 2 s, and the distance traveled is zero.
Answer:
please find the answer in the attached images , in 2 parts, btw thanks for so many points. i hope my answers are correct.
Answer:
the answer is d
Explanation:
basically the reason i think this is the answer is because the answer that i picked in this scenario to me seems like the right one and it it the one i picked on the quiz that seemed like the right one to me and i am smart and cool and awesome
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The net force needed to accelerate a 200 kg piano is 50N
According to Newton's law of motion, the formula for the net force is calculated as:
∑F = ma
Given the following parameters
Mass = 200kg
acceleration = 0.25m/s²
Substitute the given parameters into the formula
∑F = 200 * 0.25
∑F = 50N
Hence the net force needed to accelerate a 200 kg piano is 50N
Learn more here: brainly.com/question/19030143