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77julia77 [94]
3 years ago
7

Todd would like to purchase a bicycle that costs $246. This is $48 more than twice the cost of his last bicycle. How much did hi

s last bicycle cost?
Mathematics
1 answer:
Rasek [7]3 years ago
4 0
246-48= 198

198/2= 99

Todd's last bike cost $99.
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Here are yesterday's high temperatures (in Fahrenheit) in 12 U.S. cities. 48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80 Notice
irinina [24]

For the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

<h3>Measures of a Data </h3>

From the question, we are to determine the minimum, lower quartile, median, upper quartile, maximum, and interquartile range of the given data set

The given data set is

48, 50, 54, 56, 63, 63, 64, 68, 74, 74, 79, 80

Minimum = 48

Lower quartile = (54+56)/2

Lower quartile = 110/2

Lower quartile = 55

Median = (63+64)/2

Median = 127/2

Median = 63.5

Upper quartile = (74+74)/2

Upper quartile = 148/2

Upper quartile = 74

Maximum = 80

Interquartile range = Upper quartile - Lower quartile

Interquartile range = 74 - 55

Interquartile range = 19

Hence, for the given data set

Minimum = 48

Lower quartile = 55

Median = 63.5

Upper quartile = 74

Maximum = 80

Interquartile range = 19

Learn more on Measures of a Data here: brainly.com/question/15097997

#SPJ1

5 0
1 year ago
Simplify 4 to the 7th over 5 squared all raised to the 3rd power
alisha [4.7K]
<h2>Answer:</h2>

\left(\frac{4^{21}}{5^6}\right)

or

4 to the 21st over 5 to the 6th.

<h2>Step-by-step explanation:</h2>

First, we need to write our expression. Let's do it step by step:

<u>4 to the 7th:</u>

4^7

<u>5 squared:</u>

5^2

<u>4 to the 7th over 5 squared:</u>

\frac{4^7}{5^2}

<u>4 to the 7th over 5 squared all raised to the 3rd power:</u>

<u>\left(\frac{4^7}{5^2}\right)^3</u>

Using the law of exponents:

\left(\frac{4^{7\times 3}}{5^{2\times 3}}\right) \\ \\ \left(\frac{4^{21}}{5^6}\right)

Finally, the answer is 4 to the 21st over 5 to the 6th.

8 0
3 years ago
Read 2 more answers
How do I solve this?
Gelneren [198K]
I hope this helps you! 

8 0
2 years ago
I need help please!!!!!
charle [14.2K]
Obtuse angle. If wrong I’m sorry lol
5 0
2 years ago
A survey was taken of students in math classes to find out how many hours per day students spend on social media. The survey res
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I believe the answer is D.

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