If you are pushing on a box with a force of 20 N and there is a force of 7 N on the box due to sliding friction, what is the net
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Answer:
Step-by-step explanation:
I attached an image to aid the understanding of the question.
Looking at the image, we see that the 8 shaded parts are congruent, as affirmed in the question as well. And we are told that T = 3, this implies that the area of the square with T as it's side is 9ft². Since all the 8 squares are congruenrt, it means each square has its area to be 9. Therefore, the total area of the 8 shaded squares will be:
It remains the area of the shaded square with side S.
From the question, we have the following ratio:
I did not add ± because length is always positive, so the case of negative is eliminated.
Now the areas of S is
Therefore, the total area of the shaded squares is
